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allsm [11]
3 years ago
6

Select the correct answer from each drop down menu. The GCF of the numbers in the expression (32+16) is( ) The numbers left insi

de the parentheses after factoring out the GCF are ( ) and ( ) ​
Mathematics
1 answer:
lawyer [7]3 years ago
8 0

Answer:

Eu não entendo inglês!!

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Jordan invests $9,500 into an account that earns 3.25% annual interest. How much will
balandron [24]

The amount of money that Jordan will earn at the end of 10 years = $12,587.5

<h3>Calculation of compounded interests</h3>

The principal amount invested(P) = $9,500

The annual compounded daily interest rate(R) of the account = 3.25%

The time given (T) = 10 years

Simple interest (SI) = P×T × R/100

SI = 9,500×10×3.25/100

SI= 308750/100

SI= $3087.50

Therefore the total amount that would be in the account after 10 years = $9,500 + $3,087.50

= $12,587.5

Learn more about compound interest here:

brainly.com/question/24924853

#SPJ1

4 0
2 years ago
Can you help me please?
gulaghasi [49]

Answer:

I think the answer is B, because the value does increase by one

6 0
3 years ago
A=8b+c solve for b <br> Please help!
balu736 [363]

Answer:

(A-c)/8 = b

Step-by-step explanation:

A = 8b +c

A - c = b

(A-c)/8 = b

Hope this helps you!

3 0
3 years ago
Suppose ten students in a class are to be grouped into teams. (a) If each team has two students, how many ways are there to form
ValentinkaMS [17]

Answer:

(a) There are 113,400 ways

(b) There are 138,600 ways

Step-by-step explanation:

The number of ways to from k groups of n1, n2, ... and nk elements from a group of n elements is calculated using the following equation:

\frac{n!}{n1!*n2!*...*nk!}

Where n is equal to:

n=n1+n2+...+nk

If each team has two students, we can form 5 groups with 2 students each one. Then, k is equal to 5, n is equal to 10 and n1, n2, n3, n4 and n5 are equal to 2. So the number of ways to form teams are:

\frac{10!}{2!*2!*2!*2!*2!}=113,400

For part b, we can form 5 groups with 2 students or 2 groups with 2 students and 2 groups with 3 students. We already know that for the first case there are 113,400 ways to form group, so we need to calculate the number of ways for the second case as:

Replacing k by 4, n by 10, n1 and n2 by 2 and n3 and n4 by 3, we get:

\frac{10!}{2!*2!*3!*3!}=25,200

So, If each team has either two or three students, The number of ways  form teams are:

113,400 + 25,200 = 138,600

6 0
3 years ago
Which properties are best used prove a quadrilateral is a rhombus?
8_murik_8 [283]

Answer:

1) Show that the shape is a parallelogram with equal length sides

2) Show that the shape's diagonals are each others' perpendicular bisectors

3) Show that the shape's diagonals bisect both pairs of opposite angles.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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