0 = 0
Simplifying
7x + -11 = 5(x + -2) + 2x + -1
Reorder the terms:
-11 + 7x = 5(x + -2) + 2x + -1
Reorder the terms:
-11 + 7x = 5(-2 + x) + 2x + -1
-11 + 7x = (-2 * 5 + x * 5) + 2x + -1
-11 + 7x = (-10 + 5x) + 2x + -1
Reorder the terms:
-11 + 7x = -10 + -1 + 5x + 2x
Combine like terms: -10 + -1 = -11
-11 + 7x = -11 + 5x + 2x
Combine like terms: 5x + 2x = 7x
-11 + 7x = -11 + 7x
Add '11' to each side of the equation.
-11 + 11 + 7x = -11 + 11 + 7x
Combine like terms: -11 + 11 = 0
0 + 7x = -11 + 11 + 7x
7x = -11 + 11 + 7x
Combine like terms: -11 + 11 = 0
7x = 0 + 7x
7x = 7x
Add '-7x' to each side of the equation.
7x + -7x = 7x + -7x
Combine like terms: 7x + -7x = 0
0 = 7x + -7x
Combine like terms: 7x + -7x = 0
0 = 0
Solving
0 = 0
Answer: around 0.0064
i rounded it to the nearest hundred thousandth because the number will keep going on forever.
F(x) can be written as:
f(x) = Asin(2x); where A is the amplitude and the period of the function is half that of a normal sin function.
f(π/4) = 4
4 = Asin(2(π/4))
4 = Asin(π/2)
A = 4
Amplitude of g(x) = 1/2 * amplitude of f(x)
A for g(x) = 2
g(x) = 2sin(x)
The angle of rotation of triangle ABC to A'B'C is 105°
<h3>How to illustrate the information?</h3>
It should be noted that the rotation from ABC to A'B'C is in a clockwise direction.
Point B is also on the x axis and point B' is in the second quadrant.
In this case, the angle that depicts the second quadrant is 105°.
In conclusion, the correct option is D.
The complete question is:
Triangle A’ B’ C’ is the image of A B C under a rotation about the origin, (0,0)
Determine the angle of rotation
A. -105 degrees
B. -75 degrees
C. 75 degrees
D. 105 degrees
Learn more about triangles on:
brainly.com/question/11485921
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