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3 years ago

12

Jordan buys 2 baseball jersey and gloves that cost $44. She gives the clerk two fifty dollar bills to pay the exact amount. How

much Jordan pay for each jersey? Write an equation that correlated to this problem and than solve.

1 answer:

butalik [34]3 years ago

4 0

Answer: 2 ÷ 44 ≈ x x

x is 22

Step-by-step explanation:

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Komok [63]

Answer:

slim to none. He has to wear his shoes

Step-by-step explanation:

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3 years ago

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3^x.2x = 3^x + 2x-1

sattari [20]

Answer:

x=0

Step-by-step explanation:

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3 years ago

Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2

nlexa [21]

$\bold{[ \ Answer \ ]}$

$\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}$

$\bold{[ \ Explanation \ ]}$

$\bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}$

$\bold{-------------------}$

$\bold{Rewrite}$

$\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Rewrite}$

$\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}$

$\bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}$

$\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}$

$\bold{Rewrite}$

$\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}$

$\bold{Simplify}$

$\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}$

$\boxed{\bold{[] \ Eclipsed \ []}}$

3 0

3 years ago

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Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i

lana66690 [7]

In the $x,y$ plane, we have $z=0$ everywhere. So in the equation of the sphere, we have

$25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2$

which is a circle centered at (2, -10, 0) of radius 4.

In the $x,z$ plane, we have $y=0$ , which gives

$25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75$

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the $y,z$ plane, $x=0$ , so

$25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2$

which is a circle centered at (0, -10, 3) of radius $\sqrt{21}$ .

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3 years ago

Enter the explicit rule for the geometric sequence.

Sveta_85 [38]

Answer: $\frac{3}{2}$ $(\frac{1}{2})^{n-1}$

<u>Step-by-step explanation:</u>

$\frac{3}{2}, \frac{3}{4}, \frac{3}{8}, \frac{3}{16}, \frac{3}{32}, ...$

common ratio (r) = $\frac{1}{2}$

first term (a₁) = $\frac{3}{2}$

$a_{n}$ = a₁ (r)ⁿ⁻¹

= $\frac{3}{2}$ $(\frac{1}{2})^{n-1}$

4 0

3 years ago