$given \: equations \: are \\ 3x + 4y = 0 \: \: and \: 2x + 3y = 1 \\ multiply \: by \: 2 \: in \: first \: equation \\ 6x + 8y = 0 \\ multiply \: by \: 3 \: in \: second \: equation \\ 6x + 9y = 3 \\ subtracting \: the \: above \: mentioned \: equation \: \\ we \: get \: - y = - 3 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: y = 3 \\ substitute \: y = 3 \: in \: first \: equation \\ 3x + 4(3) = 0 \\ 3x = - 12 \\ x = - 4$

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7 0

2 years ago

How many dogs do I have if I give two away

Helen [10]

Answer:

Two less dogs

Your situation can be defined as x-2, where x was the number of dogs. Since the number of original dogs was not specified, two less dogs is the corrext answer

3 0

2 years ago

I need help with my homework

Lemur [1.5K]

Answer:

good for you

Step-by-step explanation:

6 0

2 years ago

What is the expression in simplest radical form

LiRa [457]

Simplify the radical by breaking up the radicand into a product of known factors.

$6\sqrt{14}$

8 0

3 years ago