3 years ago

Please help me ???????????????

Mathematics

1 answer:

vladimir2022 [97]3 years ago

7 0

Answer:

60 Bc

Step-by-step explanation:

$\sqrt{x} \sqrt{x} \frac{x}{y} \pi \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \lim_{n \to \infty} a_n \geq \int\limits^a_b {x} \, dx \left \{ {{y=2} \atop {x=2}} \right. x^{2} \sqrt{x} \sqrt{x} \pi$

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