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IgorC [24]
3 years ago
9

For the following description of data, identify the W's, name the variables, specify for each variable whether its use indicates

it should be treated as categorical or quantitative, and for any quantitative variable identify the units in which it was measured (or note that they were not provided). Specify whether the data come from a designed survey or experiment. Are the variables time series or cross-sectional? Report any concerns you have as well. An online survey of students in a large MBA Economics class at a business school in the northeastern United States asked them to report their total personal investment in the stock market (S), total number of shares of stocks currently held, total invested in mutual funds (S), and the name of each mutual fund in which they have invested. The data were used in the aggregate for classroom illustrations. Who was measured?
A. Students in a large MBA Economics class
B. Students in the northeastern United States
C. Students at a business school
D. This information is not given.
Mathematics
1 answer:
marin [14]3 years ago
3 0

Answer:

As given in the problem statement,it should be treated as quantitative Students in the northeastern United States was measured and it is a correct option B is correct option.

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1,290=h/10+h/5 What is h?​
alekssr [168]

Answer:

4300

h/10 + 2h/10

= 1290

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3h = 12,900

h = 4300

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Calculate the average between 200 and 4100
yKpoI14uk [10]
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3. The backyard of a home is a rectangle 25m by 30m. A garden of uniform width is to be
KiRa [710]

Answer:

Part A

The width of the garden is approximately 3.987 meters

Part B

Please find attached the drawing of the solution

Step-by-step explanation:

Part A

The given parameters are;

The dimensions of the backyard of the home = 25 m by 30 m

The width of the garden to be built in the yard = Uniform width

The shape of the grass left inside = Rectangular

The area of the grass at the center = The area of the garden

Let 'x' represent the width of the garden, we have;

The length of the rectangular grass area at the center, l = 30 - 2·x

The width of the rectangular area of grass at the center, w = 25 - 2·x

The area of the rectangular backyard, A = 30 m × 25 m = 750 m²

The area of the rectangular backyard, A = (The area of the garden) + (The area of the rectangle of grass inside)

The area of the rectangle of grass, GA = (30 - 2·x)·(25 - 2·x) = The area of the garden

The area of the rectangular backyard, A = 750 = (30 - 2·x)·(25 - 2·x) + (30 - 2·x)·(25 - 2·x)  = 2 × (30 - 2·x)·(25 - 2·x) = 8·x² - 220·x + 1,500

∴ 750 = 8·x² - 220·x + 1,500

8·x² - 220·x + 1,500 - 750 = 0

8·x² - 220·x + 750 = 0

x = (220 ± √(220² - 4 × 8 × 750))/(2 × 8)

x ≈ 23.513, or x = 3.987

When x = 25.513, the width of the rectangle of grass inside, w = 25 - 2 × 23.513 = -22.026, which is not a natural (physically possible)

Therefore, the possible width of the garden, x ≈ 3.987

Part B

The drawing of the solution created with MS Visio is attached

6 0
3 years ago
Can someone plz solve 2(2x -5) in distributive property
Reika [66]

Answer:

4x-10

Step-by-step explanation:

Multiply both by 2, 2x times 2 is 4x, and 5 times 2 is 10, so it becomes 4x-10.

3 0
3 years ago
Becca has a balance of $22.90 at the beginning of May for clothes. Her allotment for the month is $50.00. She buys a two new out
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Add the balance and allotment:

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She spent 85.50.

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Since she spent more than she actually could be balance would be a negative number.

The balance would be  - $12.60

4 0
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