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Diano4ka-milaya [45]
3 years ago
13

What is the slope of a line perpendicular to the line with equation 2x+3y=9

Mathematics
1 answer:
zheka24 [161]3 years ago
8 0

Answer:

<h2>slope =  \frac{3}{2}  \\</h2>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To find the slope of the perpendicular line we must first find the slope of the original line

The original line is

2x + 3y = 9

3y = - 2x + 9

y =  -  \frac{2}{3} x +  \frac{9}{  3}  \\  \\ y =  -  \frac{2}{3} x +  3

Since the lines are perpendicular to each other the slope of the perpendicular line is the negative inverse of the original line

So the slope of the perpendicular line is

slope =  \frac{3}{2}  \\

Hope this helps you

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Can someone help me please​
pishuonlain [190]

Answer:

Step-by-step explanation:

36+88+y=180

124+y=180

y=180-124

<u>y=56</u>

x+90+56=180

x+146=180

x=180-146

<u>x=34</u>

<u />

<h3><u>If you need to ask any questions, please let me know.</u></h3>
7 0
3 years ago
-3.25,<br> The greater number is<br> .<br> The number farther from 0 is
astra-53 [7]
25 and the farthest is also 24
3 0
3 years ago
What’s the value of DCB?<br> Pls help
amm1812

Answer:

78

Step-by-step explanation:

angle ACD + angle DCB = 180   (Angles on straight line)

4x + 2 + 3x + 3 = 180

7x + 5 = 180

7x = 180-5

7x = 175

x = 175 / 7

x = 25

angle DCB = 3x +3 = 3*25 + 3 = 75 +3 = 78

6 0
3 years ago
1. Write .394 as a fraction
gulaghasi [49]


.394= 197/500

you can't make it a mixed number since there isn't a whole number as with an improper fraction.

4 0
4 years ago
Read 2 more answers
Suppose that we don't have a formula for g ( x ) g(x) but we know that g ( 1 ) = − 1 g(1)=-1 and g ' ( x ) = √ x 2 + 15 g′(x)=x2
dezoksy [38]

Answer:

g(0.9) ≈ -2.6

g(1.1) ≈ 0.6

For 1.1 the estimation is a bit too high and for 0.9 it is too low.

Step-by-step explanation:

For values of x near 1 we can estimate g(x) with t(x) = g'(1) (x-1) + g(1). Note that g'(1) = 1²+15 = 16, and for values near one g'(x) is increasing because x² is increasing for positive values. This means that the tangent line t(x) will be above the graph of g, and the estimates we will make are a bit too big for values at the right of 1, like 1.1, and they will be too low for values at the left like 0.9.

For 0.9, we estimate

g(0.9) ≈ 16* (-0.1) -1 = -2.6

g(1.1) ≈ 16* 0.1 -1 = 0.6  

4 0
3 years ago
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