Answer: yes?
Step-by-step explanation:
Answer:
Three is the rate of change in the interval of 2 and 6 in the x axis.
Step-by-step explanation:
Answer: x = 8
Step-by-step explanation:
Using The Pythagorean theorem (a^2 + b^2 = c^2) we can find A or In This Case X
Plug In The Numbers:
x^2 + 6^2 = 10^2
simplify
x^2 + 36 = 100
Next, Since Were Trying To Find X And Not C, We Subtract B From C Or 36 From 100
x^2 + 36 - 36 = 100 - 36
simplify
x^2 = 64
Next, To Get Rid Of The Square, Were Going To Find The Square Root Of Both Sides Of The Equation
sqr/a = sqr/64
simplify
x = 8
Answer:
hell naw
Step-by-step explanation:
Answer:
<11,33>
Step-by-step explanation:
If it is perpendicular to <3,-1> We can use <0,0> as the other point to get the slope
m = (y2-y1)/(x2-x2)
The slope of the vector is
(-1-0)/(3-0)
= -1/3
Then we want a vector perpendicular, so we take the negative reciprocal of the slope
- (-3/1) =3
So the perpendicular slope is 3
Our new vector y/x = 3/1
Using cross products
3x=y
The magnitude has to be 11 sqrt (10)
magnitude = sqrt( ((x)^2 + y^2) = 11sqrt(10)
magnitude = sqrt( ((x^2 + y^2) = 11sqrt(10)
Square both sides
x^2+y^2 = 11^2*10
x^2 + y^2 =1210
We have 2 equations and 2 unknowns
x^2 +y^2 =1210 and
3x=y
Replace y with 3x
x^2 + (3x)^2 =1210
x^2 +9x^2 =1210
10x^2 =1210
Divide both sides by 10
x^2 =121
Take the square root of each side
sqrt(x^2) = sqrt(121)
x=±11
But it problems states it has to be in the first quadrant so x=11
x =11
Now we can find y
y =3x
y =11*3
y =33
The vector is <11, 33>