Please help asap 28 pts

Mathematics

2 answers:

butalik [34]3 years ago

3 0

I think its A not sure on this one but
can you send me a message so you can help me with pysics and ill help u with this

Otrada [13]3 years ago

3 0

The answer to this question is A

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A bag of potatoes weighs 7 and 1/2 pounds. Of the potatoes in the bag, 1/6 are rotten. What is the weight of the good potatoes?

Finger [1]

Answer:

one sixth of 7.5 pounds is 1.25, so 7.5 minus the rotten 1.25 is 6.25.

Step-by-step explanation:

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2 years ago

The value of a graphing calculator is $225. After 2 years, the value of this calculator is $160. Find the value of the calculato

OlgaM077 [116]

To find the value of the calculator after 5 years, you need to find how much the price of the calculator drops each year. From years 0 to 2, it seems that the price of the calculator has dropped by some amount of money x. To find how much the calculator drops each year, first you will need to subtract 160 from 225 (225-160) to get 65. Next, you need to divide 65 by 2 (65/2) to get $32.50.

I believe that in order to find the price after 5 years, you will need to multiply 32.5 by 5 (32.5*5) to get $162.50. Next you would subtract $162.50 from $225 (225.00-162.50) to get $62.50.

So, the price of the calculator after 5 years is $62.50!

I hope this helps!

3 0

2 years ago

A 52 foot ladder is set against the side of the house so that it reaches up 48 feet .if jevonte grabs the ladder at its base and

Vesnalui [34]

Answer:

Step-by-step explanation:

The way to approach this that makes the most sense to a student would be to find out how far from the house the ladder currently is, then add 3 feet to that and do the problem all over again. This is right triangle stuff...Pythagorean's Theorem in particular. The ladder is the hypotenuse, 52 feet long. The height of the rectangle is the distance the ladder is up the side o the house, 48 feet. We plug those into Pythagorean's Theorem and solve for the distance the ladder is from the house:

$52^2=48^2+x^2$ and

$2704=2304+x^2$ and

$x^2=400$ so

x = 20. Now if we add the 3 feet that the ladder was pulled away from house, the distance from the base of the ladder to the house is 23 feet, the ladder is still 52 feet long, but what's different is the height of the ladder up the side of the house, our new x:

$52^2=23^2+x^2$ and