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3 years ago

Please this will determine if I pass

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

5 0

The answer is B through ASA (Angle-Side-Angle) similarity criterion.

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Blank divided by 7>800

djverab [1.8K]

Hi there

Replace the blank space by x

so x/7 > 800
All you have to do is cross-multiply

x > 7*800
x> 5600

I hope that's help !

8 0

3 years ago

Read 2 more answers

Please solve this, will rate 5 stars and mark as STAR!

Nina [5.8K]

Answer:

$\boxed{5 \cdot \sqrt{2} \cdot \sqrt[6]{5} }$

Step-by-step explanation:

$\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$\sqrt{\sqrt[3]{10} } \implies (10^\frac{1}{3} )^\frac{1}{2} =10^\frac{1}{6} =\sqrt[6]{10}$

$\therefore \sqrt{\sqrt[3]{10} }=\sqrt[6]{10}$

$\text{Solving }\sqrt[3]{250} \cdot \sqrt{\sqrt[3]{10} }$

$250=2 \cdot 5^3$

$\sqrt[3]{250}=\sqrt[3]{2\cdot 5^3}=5 \sqrt[3]{2}$

Once

$\sqrt[6]{2} \cdot \sqrt[6]{5} = \sqrt[6]{10}$

We have

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5}$

We can proceed considering the common base of exponentials

$\sqrt[3]{2} \cdot \sqrt[6]{2} = 2^{\frac{1}{3}} \cdot 2^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} }=\sqrt{2}$

Therefore,

$5 \sqrt[3]{2} \cdot \sqrt[6]{2} \cdot \sqrt[6]{5} = 5 \cdot \sqrt{2} \cdot \sqrt[6]{5}$

7 0

3 years ago

Lyric spent half of his weekly allowance at the movies. To earn more money, his parents let him clean the windows in the house f

rusak2 [61]

Answer:

This question does not make since.

Step-by-step explanation:

7 0

3 years ago

What would the answer be

Hoochie [10]

Answer:

Step-by-step explanation:

process of elimination. the red dot is not a 1/4 of the number of lines, so it cant be 12.25, 13.625 is impossible because it has a value less than 13, and 12.625 is impossible as well because it has a value less than 12.5 therefore 12.375 is the best answer, and the only correct answer

4 0

3 years ago

Help pls I really need it pls

Marianna [84]

The value of x is 7 because 8/24 = 1/3 so find 1/3 of 21

4 0

3 years ago