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Sonbull [250]
3 years ago
9

The point (−3, 1) is on the terminal side of angle Θ, in standard position. What are the values of sine, cosine, and tangent of

Θ? Make sure to show all work. (10 points)
Mathematics
2 answers:
inn [45]3 years ago
8 0
The angle is in the second quadrant  so only the sine is positive . 
Length of the hypotenuse = sqrt (-1^2 + 3^2)  = sqrt10
sine  =  1/sqrt10 =  0.3162 to 4 dec places
tangent = 1 / -3 =  -0.3333  to 4 d p's
cosine = -3/sqrt10 = -0.9487 to 4 d, p's.
Brrunno [24]3 years ago
8 0

To solve this problem yo need to have the "x", the "y", and the radius. To find the radius since it is not given we use the formula.

sq rt(-3^2+1^2)

sq rt(9+1)

sq rt(10) would be the length of the radius in this case.

Then we use the sine cosine and tangent fractions

sin:y/r

cos:x/r

tan:y/x

With the values plugged in the equations are

SIN:1/sqrt(10) Since there can´t be a sq rt in hte denominator we change it to 1(sq rt(10))/10

COS:-3/sqrt(10) Since there can´t be a sq rt in the denominator we change it to -3(sq rt(10))/10

TAN:1/-3 This one can stay the same.

This would be the measures of SIN, COS, and TAN.

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Sesame Company purchased a computer system for $74,000 on January 1, 2018. It was depreciated based on a 7-year life and an $18,
amm1812

Answer: $24000

Step-by-step explanation:

Depreciation for 2018 = ($74,000 - $18000) / 7

= $56000/7

= $8000

Depreciation for 2019 = ($74,000 - $18000) / 7

= $56000/7

= $8000

Depreciation up to 2019 = $8000 + $8000 = $16000

Book value at end of 2019 = $74000 - $16000 = $58000

Revised residual value = $10,000

Number of remaining years = 4-2 = 2 years

Depreciation expensed for 2020 will be:

= ($58000 - $10,000) / 2

= $48000/2

= $24000

7 0
3 years ago
Given that f(x) = x2 + 12x + 32 and g(x) = x+ 4, find (f - g)(x) and
frosja888 [35]

Answer:

x²+11x+28

Step-by-step explanation:

(f - g) (x) = f(x) - g(x)

x² + 12x + 32 - (x + 4) = x² + 11x + 28

6 0
3 years ago
here are several types of objects. For each type of object, estimate how many there are in a stack that is 5 feet high. Be prepa
lorasvet [3.4K]

We need to estimate how tall is, on average, one of these object, and then count how many would be in a 5 feet high stack.

For example, on Google you may see that "1.5 cubic foot boxes are the standard box, manufactured by most companies". So, we assume that a standard cardboard box is 1.5 feet tall.

So, if we set the equation

1.5k = 5 \iff k=\dfrac{5}{1.5}=3.\bar{3}

So, there would be between 3 and 4 cardboard boxes in a 5 feet tall stack.

Similarly, we can see that the average book is 9 inches tall. 9 inches are 0.75

feet, so we have

0.75k=5 \iff k=6.\bar{6}

So, there would be between 6 and 7 books in a 5 feet tall stack.

The average brick is 75 millimeters tall, which means 0.25 feet tall. Again, we have

0.25k=5 \iff k=20

So, there would be 20 bricks in a 5 feet tall stack.

Finally, a coin is about 0.006 feet, which leads to

0.006k=5 \iff k=833.\bar{3}

So, there would be between 833 and 834 coins in a 5 feet tall stack.

5 0
3 years ago
Which of the following scales of measurement lacks numeric properties?
Rus_ich [418]

Answer: A

Step-by-step explanation:

The nominal scale by definition only deals with non-numeric or non-quantitative variables or where numbers have no numerical value. The nominal scale uses tags or labels instead of number to classify or identify an object being measured.

5 0
3 years ago
Slove the following <br>equation without with out transporting I)5y +10=4y-10​
Katen [24]
The answer is y= -20
7 0
3 years ago
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