Question

Which of the following are solutions to the equation below?

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}$

Let's solve the given equation ~

$\qquad \tt \dashrightarrow \:4 {x}^{2} + 20x + 25 = 49$

$\qquad \tt \dashrightarrow \:4 {x}^{2} + 20x + 25 - 49 = 0$

$\qquad \tt \dashrightarrow \:4 {x}^{2} + 20x - 24 = 0$

$\qquad \tt \dashrightarrow \:4( {x}^{2} + 5x - 6) = 0$

$\qquad \tt \dashrightarrow \: {x}^{2} + 5x - 6 = 0$

$\qquad \tt \dashrightarrow \: {x}^{2} + 6x - x - 6 = 0$

$\qquad \tt \dashrightarrow \:x(x + 6) - 1(x + 6) = 0$

$\qquad \tt \dashrightarrow \:(x + 6)(x - 1) = 0$

Hence, we get -6 and 1 as our roots ~

So, the correct choices are : B and D