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jarptica [38.1K]
2 years ago
14

Which of the following are solutions to the equation below?

Mathematics
1 answer:
nalin [4]2 years ago
3 0

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve the given equation ~

\qquad \tt \dashrightarrow \:4 {x}^{2}  + 20x + 25 = 49

\qquad \tt \dashrightarrow \:4 {x}^{2}  + 20x + 25  -  49 = 0

\qquad \tt \dashrightarrow \:4 {x}^{2}  + 20x - 24 = 0

\qquad \tt \dashrightarrow \:4( {x}^{2}  + 5x - 6) = 0

\qquad \tt \dashrightarrow \: {x}^{2}  + 5x - 6 = 0

\qquad \tt \dashrightarrow \: {x}^{2}  + 6x - x - 6 = 0

\qquad \tt \dashrightarrow \:x(x + 6) - 1(x + 6) = 0

\qquad \tt \dashrightarrow \:(x + 6)(x - 1) = 0

Hence, we get -6 and 1 as our roots ~

So, the correct choices are : B and D

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Answer:

A.  x = 3/k.

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