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natka813 [3]
3 years ago
6

HELP ME PLEASE!!! What is the value of y for the parallelogram shown A. 66 B. 60 C. 22 D. 38

Mathematics
1 answer:
Nesterboy [21]3 years ago
5 0

Answer:

<h2><em>2</em><em>2</em></h2>

<em>Option </em><em>C</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>correct</em><em> </em><em>option</em><em>.</em>

<em>Solu</em><em>tion</em><em>,</em>

<em>3y = 66</em>

<em>(</em><em>opposite</em><em> </em><em>angles</em><em> </em><em>of</em><em> </em><em>parallelog</em><em>ram</em><em> </em><em>are</em><em> </em><em>equal </em><em>)</em>

<em>or  \: 3 \times y = 66 \\ or \: y =  \frac{66}{3}  \\ y = 22</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> </em><em>y</em><em>our</em><em> assignment</em><em>.</em><em>.</em>

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How much bigger is the Sum of first 50 even numbers than the sum of first 50 odd numbers?
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Answer:

50

Step-by-step explanation:

Sum Even numbers

n = 50

d = 2

a1 = 2

The last number is

an = a1 + (n-1)d

an = 2 + (50 - 1)*2

an = 2 + 49 * 2

an = 2 + 98

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Sum of the even numbers

Sum = (a1 + a50)*n/ 2

Sum = (2 + 100)*50/2

sum = 102 * 25

sum = 2550

Sum of the first 50 odd numbers

a1 = 1

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Find l

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l = 1 + 49*2

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The difference and answer is 2550 - 2500  = 50

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3 years ago
Hello! Please answer this ASAP! Its a math question..
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  1. The hikers carried 17.5 litres of water
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In a survey, three out of four students said that courts show too much concern for criminals. Of seventy randomly selected stude
vladimir1956 [14]

Answer:

B. Yes, because P(X ≥ 68) ≤ .05

Step-by-step explanation:

The probability of a score X occuring is said to be unusually high if the probability of a score of X or larger is lower than 5%.

For each student, there are only two possible outcomes. Either they think that the court shows too much concern for criminals, or they do not think this. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

Three out of four students said that courts show too much concern for criminals. This means that p = \frac{3}{4} = 0.75

Would 68 be considered an unusually high number of students who feel that courts are partial to criminals?

We have to find P(X \geq 68).

P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 68) = C_{70,68}.(0.75)^{68}.(0.25)^{2} < 0.000001

P(X = 69) = C_{70,69}.(0.75)^{69}.(0.25)^{1} < 0.000001

P(X = 70) = C_{70,70}.(0.75)^{70}.(0.25)^{0} < 0.000001

So

P(X \geq 68) = P(X = 68) + P(X = 69) + P(X = 70) < 0.000003

P(X \geq 68) is lower than 0.05, so this is an unusually high number.

So the correct answer is:

B. Yes, because P(X ≥ 68) ≤ .05

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