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scZoUnD [109]
3 years ago
7

Mike has a net spendable income of $1,400. He decides to set up a budget before looking for an apartment or a car. He sets up hi

s budget and finds that he has lots of money left over. He puts the extra money into entertainment.
Housing $420
Food $168
Transportation $210
Insurances $42
Debts $70
Entertainment $224
Clothing $70
Savings $70
Medical $56
Miscellaneous $70
Why might this budget be a problem?


A.) Mike will spend more money than he is earning.

B.) Mike does not have enough money budgeted for food or medical expenses.

C.) Mike is using the minimum recommended percentages for food, housing, and transportation. The costs are likely to exceed the expenses in each category.

D.) Mike has not budgeted all of his money. He will find that he has extra money at the end of the month, which will end up being wasted.
Mathematics
2 answers:
Shtirlitz [24]3 years ago
7 0

C.) Mike is using the minimum recommended percentages for food, housing, and transportation. The costs are likely to exceed the expenses in each category.


Triss [41]3 years ago
5 0

Answer:

Option C is the answer.

Step-by-step explanation:

Mike has a net spendable income of $1,400.

His total budget is :

Housing =$420

Food=$168

Transportation=$210

Insurances=$42

Debts=$70

Entertainment=$224

Clothing=$70

Savings=$70

Medical=$56

Miscellaneous=$70

420+168+210+42+70+224+70+70+56+70=1400

So, out of all the given options, the correct one seems to be :

Mike is using the minimum recommended percentages for food, housing, and transportation. The costs are likely to exceed the expenses in each category.

Therefore, we can say that Mike should budget properly as he is spending more on entertainment, rather than more important categories.

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A line has the equation y = 3x + 16 what are the coordinates of the y intercept of the line?
bearhunter [10]

Answer:

(0, 16)

Step-by-step explanation:

  • y = 3x + 16

  • Plug x = 0

  • -> y = 3*0 + 16

  • -> y = 0 + 16

  • -> y = 16

  • -> y- intercept = (0, 16)
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2 years ago
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Which equation represents a line which is parallel to the line y = 5x – 5?
Fudgin [204]

Answer:

C) y-5x=2

Step-by-step explanation:

y-5x=2

y=5x+2 parrallel to y=5x-5

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8 0
3 years ago
Javier and his study group designed a word problem, equation, table, and graph that were all supposed to represent the same info
kow [346]

Graph is your answer look below for proof

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3 0
3 years ago
Can someone please help me with this question
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Answer:

Step-by-step explanation:

I don't know xd

6 0
3 years ago
For the hypothesis test H0: μ = 10 against H1: μ >10 and variance known, calculate the Pvalue for each of the following test
Basile [38]

Answer:

a) p_v =P(Z>2.05)=1-P(z

b) p_v =P(Z>-1.84)=1-P(z

c) p_v =P(Z>0.4)=1-P(z

Step-by-step explanation:

Some previous concepts

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.

A z-test for one mean "is a hypothesis test that attempts to make a claim about the population mean(μ)".

The null hypothesis attempts "to show that no variation exists between variables or that a single variable is no different than its mean"

The alternative hypothesis "is the hypothesis used in hypothesis testing that is contrary to the null hypothesis"

Hypothesis

Null hypothesis: \mu=10

Alternative hypothesis: \mu >10

If the random variable is distributed like this: X \sim N(\mu,\sigma)

We assume that the variance is known so the correct test to apply here is the z test to compare means, the statistic is given by the following formula:

z_o=\frac{\bar X -\mu}{\sigma}

Since we have the values for the statistic already calculated we can calculate the p value using the following formulas:

Part a

p_v =P(Z>2.05)=1-P(z

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(2.05,0,1,TRUE)"

Part b

p_v =P(Z>-1.84)=1-P(z

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(-1.84,0,1,TRUE)"

Part c

p_v =P(Z>0.4)=1-P(z

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(0.4,0,1,TRUE)"

Conclusions

If we use a reference value for the significance, let's say \alpha=0.05. For part a the p_v so then we can reject the null hypothesis at this significance level.

For part b the p_v>\alpha so then we FAIL to reject the null hypothesis at this significance level.

For part c the p_v>\alpha so again we FAIL to reject the null hypothesis at this significance level.

3 0
3 years ago
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