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timofeeve [1]
3 years ago
6

What is 3 copies of 1/3

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer: 1

Step-by-step explanation:

3 copies of 1/3 would be 1/3+1/3+1/3= 1

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Identify the class midpoints for the given frequency distribution.
german

Answer:

s

Step-by-step explanation:

8 0
3 years ago
I need help with my math
PolarNik [594]

Hello There!

The correct answer would be "B" this is because we are taking 6 and multiply it by our x column which is the "in" column and adding 1 to what we get.

8 0
3 years ago
Read 2 more answers
Which of the following points are solutions to the system of inequalities shown below?
Ira Lisetskai [31]
Y > 6x + 5
y < -6x + 7
(2,17)
17 > 6(2)+5 ; 17> 17 NO
(8,8)
8>6(8)+5 NO
(-2,18)
18>6(-2)+5
18>-7 YES
18< -6(-2)+7
18< 12+7 YES (-2,18) is an answer
(0,6)
6>6(0)+5
6>5 YES
6<-6(0)+7
6<7 YES (0,6) is an answer
(-2,19)
19>6(-2)+5
19>-7 NO
(2,18)
18>6(2)+5
18>17 YES
18< -6(2)+7
18< -5 NO

3 0
3 years ago
Find the exact value of the given expression.<br> sin(2cos^-1(5/13))
xeze [42]

Answer:

+120/169 or -120/169

Step-by-step explanation:

  • let cos^{-1}[\frac{5}{13}  ] = \alpha

where, alpha is some angle that satisfies the assumed condition.

  • so, cos\alpha= 5/13

[ taking cos to the other side  or applying cos on both sides]

  • now, substitute this in the given expression
  • sin(2cos^-1(5/13)) = sin(2\alpha )

as sin\beta =  + or -\sqrt{1-(cos\beta) ^{2}

[by general trigonometry formula: cos^{2}[\beta]  +sin^{2}[\beta]=1]

so if  cos\alpha= 5/13, we can get sin\alpha from the above formula as + or - 12/13

(because, after taking square root on both sides we keep + or -]

  • as, sin2\beta  = 2*sin[\beta ]*cos[\beta ]

[by general trigonometry formula]

  • here, now sin[2\alpha ]=2*(+or- 12/13)*5/13\\

so, the final value can be 120/169 or -120/169.

4 0
3 years ago
A school raised &amp;4,589 in a sale. Mr Simmons class raised 1/100 of the money. How much did Mr Simmons class raise?
Ksenya-84 [330]

Alright, lets get started.

total amount school raised in sale = $ 4589

Mr Simmons class raised \frac{1}{100} of the money.

So, if we want to find amount of the money Mr. Simmons raised, we sould take one hundered of the total amount.

Hence money raised by Mr. Simmons class = \frac{1}{100} * 4589

Hence money raised by Mr. Simmons class = \frac{4589}{100}

Hence money raised by Mr. Simmons class = $ 45.89 : Answer

Hope it will help :)


4 0
3 years ago
Read 2 more answers
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