Answer:
I'm pretty sure the answer is broken
Explanation:
Answer:
-4.8 m/s²
Explanation:
Apply Newton's second law:
∑F = ma
F − mg = ma
300 N − (60 kg) (9.8 m/s) = (60 kg) a
a = -4.8 m/s²
The acceleration five seconds after jumping is 4.8 m/s² downward.
Complete question:
A hydraulic jack is used to lift a car by applying a force of 120N at the pump piston, if the area of the ram and pump piston are 100cm squared and 1m squared respectively. What is the weight of the car?
Answer:
the weight of the car is 1.2 N
Explanation:
Given;
applied force, F₁ = 120 N
area of the effort (pump), A₁ = 1 m²
area of the load (ram), A₂ = 100 cm² = 1 x 10⁻² m²
let the weight of the car = F₂
The applied pressure is constant and the following equations can be used to calculate the weight of the car.
Therefore, the weight of the car is 1.2 N
' +4 m/s² ' means that the pigeon's speed is 4 m/s greater every second.
Starting from zero speed, after 10 seconds, its speed is
(10 x 4m/s) = 40 m/s.
We can't say anything about its velocity, because we have
no information regarding the direction of its flight.