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hodyreva [135]
3 years ago
8

A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.

Physics
1 answer:
ella [17]3 years ago
8 0

Answer:

a. 17 μC b. 14.45 J

Explanation:

Here is the complete question

A pair of 10μF capacitors in a high-power laser are charged to 1.7 kV.

a. What charge is stored in each capacitor?

b. How much energy is stored in each capacitor?

a. The charge Q stored in a capacitor is Q = CV where C = capacitance  and V = voltage. Here, C = 10μF = 10 × 10⁻⁶ F and V = 1.7 kV = 1.7 × 10³ V.

So, Q = CV = 10 × 10⁻⁶ × 1.7 × 10³ = 1.7 × 10⁻² C = 17 × 10⁻³ C = 17 μC

b. The energy stored in a capacitor is given by W = 1/2CV² = 1/2 × 10 × 10⁻⁶ F × (1.7 × 10³ V)² =  1/2 × 10 × 10⁻⁶ F × 2.89 × 10⁶ V² = 1/2 × 10 × 2.89 × 10⁶ × 10⁻⁶ J = 14.45 J

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3 years ago
A light ray hits a plane surface at 20 degrees. What is the angle between the incident and reflected rays.
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140°

Explanation:

The law of reflection states that the angle of redlection equals to the angle of incidence.

When light rays hit surface at 20°, they also leave the surface at the same angle

Since the whole surface has 180° then subtracting these two angles from total angle gives the the angle between the incident and reflected rays.

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A student team is to design a human powered submarine for a design competition. The overall length of the prototype submarine is
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b) The drag force is 10.32 N

Explanation:

a) The Reynold´s number for the model and prototype is:

Re_{m} =\frac{p_{m}V_{m}L_{m}   }{u_{m} }

Re_{p} =\frac{p_{p}V_{p}L_{p}   }{u_{p} }

Equaling both Reynold's number:

\frac{p_{p}V_{p}L_{p}   }{u_{p} }=\frac{p_{m}V_{m}L_{m}   }{u_{m} }

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b) The drag force is:

\frac{F_{Dm} }{p_{m}V_{m}^{2}L_{m}^{2}     } =\frac{F_{Dp} }{p_{p}V_{p}^{2}L_{p}^{2}     } \\F_{Dp} =\frac{F_{Dp}p_{p}V_{p}^{2}L_{p}^{2} }{p_{m}V_{m}^{2}L_{m}^{2}     } \\F_{Dp}=\frac{2.3*999.1*0.56^{2} *8^{2} }{1.184*61.42^{2}*1^{2}  } =10.32N

6 0
3 years ago
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