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4 years ago

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Select the correct answer. Ben has $10 to spend on dinner. He can have a pizza delivered, drive to a burger place, or go to the

grocery store to get ingredients for a fresh salad. In the end, he goes with the salad. If each meal would have cost him the same amount, what is Ben’s incentive for choosing salad? A. to eat a healthier meal B. to help the local economy C. to save gas D. to save on his telephone bill

1 answer:

Rudik [331]4 years ago

5 0

Answer:

A. to eat a healthier meal

Explanation:

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A cylinder that is 20 cm tall is filled with water. If a hole is made in the side of the cylinder 5 cm below the top level, how

lara31 [8.8K]

Answer:

See description

Explanation:

This is an example where we need Tornicelli's law, which states that the horizontal speed of a fluid that starts falling from an orifice is the same speed that an object acquires from free-falling.

$v = \sqrt{2gh}$

we are given:

$h_{cilinder} = 0.2 [m]\\h = 0.05 [m]\\d=0.15[m]$

the horizontal velocity of the water at the start is:

$v = \sqrt{2(9.8)(0.05)}=0.989949 [m/s]=1[m/s]$

now we need to find the time for the water drops to fall d:

as the gravity is the only force interacting with the water we have:

$y(t) = \frac{1}{2} g*t^2$

replace for y = d

$0.15 = \frac{1}{2} g*t^2=>t=\sqrt{\frac{2*0.15}{9.8}}=0.1749[s]$

now that we have t we notice that there are no horizontal forces interacting with the water, so the horizontal position is given by:

$x(t)=v*t$

Finally, we replace v and t:

$x(2.45) = 1*0.1749 = 0.1749 [m]=17.49[cm]$

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3 years ago

.If Nellie Newton pushes an object with twice the force for twice the distance, she does

Vanyuwa [196]

ur answer would be 4x the work!!!

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3 years ago

The main light gathering device of a refractor telescope is

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It's the "objective" lens ... the big one in the front.

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3 years ago

A hollow sphere of radius 0.200 m, with rotational inertia I = 0.0484 kg·m2 about a line through its center of mass, rolls witho

d1i1m1o1n [39]

Answer:

Part a)

$KE_r = 8 J$

Part b)

v = 3.64 m/s

Part c)

$KE_f = 12.7 J$

Part d)

$v = 2.9 m/s$

Explanation:

As we know that moment of inertia of hollow sphere is given as

$I = \frac{2}{3}mR^2$

here we know that

$I = 0.0484 kg m^2$

R = 0.200 m

now we have

$0.0484 = \frac{2}{3}m(0.200)^2$

$m = 1.815 kg$

now we know that total Kinetic energy is given as

$KE = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2$

$KE = \frac{1}{2}mv^2 + \frac{1}{2}I(\frac{v}{R})^2$

$20 = \frac{1}{2}(1.815)v^2 + \frac{1}{2}(0.0484)(\frac{v}{0.200})^2$

$20 = 1.5125 v^2$

$v = 3.64 m/s$

Part a)

Now initial rotational kinetic energy is given as

$KE_r = \frac{1}{2}I(\frac{v}{R})^2$

$KE_r = \frac{1}{2}(0.0484)(\frac{3.64}{0.200})^2$

$KE_r = 8 J$

Part b)

speed of the sphere is given as

v = 3.64 m/s

Part c)

By energy conservation of the rolling sphere we can say

$mgh = (KE_i) - KE_f$

$1.815(9.8)(0.900sin27.1) = 20- KE_f$

$7.30 = 20 - KE_f$

$KE_f = 12.7 J$

Part d)

Now we know that

$\frac{1}{2}mv^2 + \frac{1}{2}I(\frac{v}{r})^2 = 12.7$

$\frac{1}{2}(1.815) v^2 + \frac{1}{2}(0.0484)(\frac{v}{0.200})^2 = 12.7$

$1.5125 v^2 = 12.7$

$v = 2.9 m/s$

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3 years ago

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Limestone, Sandstone, and Shale would be the answer.

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