Answer:
E= 55.53 x 10³ V/m
Explanation:
Given that
a= 3.63 cm
Area ,A= a²
distance ,d= 0.473 mm
Stored energy ,U = 8.49 nJ
Value of capacitor given as

By putting the values

C=2.46 x 10⁻¹¹ F

V=Voltage difference


V=26.27 V
V= E d
E=Electric filed
26.27 = E x 0.473 x 10⁻³
E= 55.53 x 10³ V/m
Sound waves.
Eathquake P-Waves
Answer:
4
Explanation:
We are given that

K.E at x=0 m=20 J
K.E at x=3 m=11 J
We have to find the value of c.
By work energy theorem
Work done=Change in kinetic energy
W=
![W=[\frac{cx^2}{2}-x^3]^{3}_{0}](https://tex.z-dn.net/?f=W%3D%5B%5Cfrac%7Bcx%5E2%7D%7B2%7D-x%5E3%5D%5E%7B3%7D_%7B0%7D)






I believe that it is a boy but if they would like to be classified as a girl or a boy their decision needs to be respected
Answer:
Velocity,v = 0.323 m/s
Explanation:
The acceleration of a particle is given by :

b = 0.8 m when x = 0
Since,

![\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]+c](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%5E2%7D%7B2%7D%3D-%5B0.1x-0.8cos%5Cdfrac%7Bx%7D%7B0.8%7D%5D%2Bc)
At x = 0, v = 1 m/s


![\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]-0.3](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%5E2%7D%7B2%7D%3D-%5B0.1x-0.8cos%5Cdfrac%7Bx%7D%7B0.8%7D%5D-0.3)
At x = -1 m


v = 0.323 m/s
So, the velocity of the particle is 0.323 m/s. Hence, this is the required solution.