How do you solve 58ad/b ?
2 answers:
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Answer:
Step-by-step explanation:
Hello!
You have the growth of 12 plants over a week (cm)
To construct a box plot you have to identify the 1st, 2nd, and 3rd Quartiles for the box and the maximum and minimum values for the whiskers.
Box
1st Quartile (Q₁)
Is the value of the data set that separates the bottom 25% from the top 75%. First, you need to calculate its position:
PosQ₁= n/4= 12/4= 3
So the first quartile is the third value.
6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14
Q₁= 7
2nd Quartile/ Median (Q₂/Me)
PosMe= 12/2= 6
The second quartile in the 6th value.
6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14
Q₂=Me= 8
3rd Quartile (Q₃)
PosQ₃= n*(3/4)= 12*(3/4)= 9
The third quartile is the 9th value.
6, 7, 7, 8, 8, 8, 9, 9, 10, 11, 11, 14
Q₃= 10
The left whisker extends from the Q₁ to the minimum value.
The right whisker extends from the Q₃ to the maximum value.
Min= 6
Max= 14
'------| | |-------'
6 7 8 10 14
The box plot that best displays a summary of the data, is C.
I hope this helps!
