Answer:
f(x) and g(x) have the same x-intercepts (is <em>not true</em>)
Step-by-step explanation:
g(x) is a reflection across the y-axis and a horizontal compression of f(x). In general those transformations will move the x-intercepts. (The y-intercept and the number of x-intercepts will remain unchanged.)
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<em>Comment on the question/answer</em>
f(x) = x^3 is a 3rd degree polynomial. When transformed to g(x) = -8x^2, its only x-intercept (x=0) remains the same. The answer above will not apply in any instance where the only x-intercept is on the line of reflection. (The question is flawed in that it does not make any exception for such functions.)
Answer:
last choice
Step-by-step explanation:
If we are looking at positive integers and we take out the odd ones, the only one's that are left are the even ones.
So last choice. (Also I assume AC meant the complement of A)
In any square the diagonal = a*sqrt(2), where a = length of any side (in a square all sides are equal in length)
*BTW sqrt(2) = radical 2... Just to be sure it's <span>intelligible...
</span>
Soo... if the diagonal = 8*sqrt(2) cm, then the side (a) = 8 cm.
:-)
√26+13 ² = (x+7)²
26x + 13 = X² +14X + 49
26X +13 - X² -14X - 49 = 0
12X - X² - 36 = 0
-(X²-12X+36) = 0
-(X-6)² = 0
(X-6)² = 0
X-6 = 0
X= 6
