<span>y = tan^−1(x2/4)</span>
tan(y) = x2/4
sec2(y) = x/2
y′ = xcos^2(y)/2
<span>cos^2(y) = <span>16x2+16</span></span>
<span>y′ = <span>8x/(<span>x2+16)
let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (</span></span></span>x2 <span>+ 16)
y at x =0 = </span> 4 ln (<span>16) = 11.09</span>
Answer: how do you solve for this
Step-by-step explanation:
Answer:
B on ed 2020
Step-by-step explanation:
an r value of 1 would be a graph that has a linear line going up one then
to the right one so the closest to that is the 2nd graph (B)
Answer:
-5x³ -5x² -9x - 4
Step-by-step explanation:
(-6x³-4x²-8)+(x³-x²-9x+4)
Add the like terms.
-6x³ and x³ are like terms. -6x³ + x³ = -5x³
-4x² and -x² are like terms. -4x² - x² = -5x²
-8 and 4 are like terms. -8 + 4 = -4
-6x³-4x²-8 +x³-x²-9x+4 = -5x³ -5x² -9x - 4
Answer:
-2g -10
Step-by-step explanation:
On simplifing this expression we get,
-2(g+5)
=> -2g + (-10)
=> -2g - 10
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