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4 years ago

Multiply and simplify. Question is in the picture.

Mathematics

2 answers:

frez [133]4 years ago

5 0

The answer should be b¹². You add the exponents of each constant. In the case of the simple b the exponent would be one.

Bess [88]4 years ago

3 0

$Use\\\\a^n\cdot a^m=a^{n+m}\\\\b^2\cdot b^4\cdot b\cdot b^5=b^{2+4+1+5}=\boxed{b^{12}}$

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If f(x) = 2x-5, which expression represents f(x+1)

ra1l [238]

F(x)=2x-5
Insert the value of x which is x+1 ->
F(x+1)= 2(x+1)-5
Distribute ->
F(x+1)=2x+2-5
Then, add like terms->
F(x+1)=2x-3

4 0

3 years ago

Read 2 more answers

A normal distribution has a mean of 60 and a standard deviation of 2. Determine the z-

a_sh-v [17]

Answer: z score is -19

Work Shown:

x = 22 is the raw score

mu = 60 is the mean

sigma = 2 is the standard deviation

z = (x-mu)/sigma = formula to find z scores

z = (22 - 60)/2

z = -38/2

z = -19

The z score of -19 means we are 19 standard deviations below the mean. Anything beyond 3 standard deviations is often considered unusual/rare as most of the data in the normal distribution is within 3 standard deviations (approximately 99.7% of the distribution)

6 0

3 years ago

What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

Step(i):-

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

step(ii):-

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

step(iii):-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

Conclusion:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

5 0

3 years ago

Plz help asap!!!!!!!!!!!!!!!!

Anna11 [10]

Answer:

The answer is D, as the trapezoid will not change at all due to the fact that it is just being rotated. (Rotations do not change a shape's measures or shape). :)

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Is 7/11 and 42/60 proportional?

il63 [147K]

No they arent proportional

6 0

3 years ago