All categories

3 years ago

Multiply and simplify. Question is in the picture.

Mathematics

2 answers:

frez [133]3 years ago

5 0

The answer should be b¹². You add the exponents of each constant. In the case of the simple b the exponent would be one.

Bess [88]3 years ago

3 0

$Use\\\\a^n\cdot a^m=a^{n+m}\\\\b^2\cdot b^4\cdot b\cdot b^5=b^{2+4+1+5}=\boxed{b^{12}}$

You might be interested in

Solve for x using the correct order operations

Mice21 [21]

Answer:

B: x = -12

Step-by-step explanation:

12 - (3 × 2)^2 + 4 × 3

Use PEMDAS, meaning solve what's in the parentheses first (P stands for parentheses)

12 - (6)^2 + 4 × 3

We get 6 because 3 × 2 = 6

Next step is solve any exponents (E for exponents)

12 - 36 + 4 × 3

We get 36 because 6 × 6 = 36 (the exponent was 2 meaning multiply the same number, 6, twice: 6 × 6)

Now we move on to multiplication and division (M for multiplication and D for division)

These are interchangable in that either can go first depending on its location in the equation

However, since there is no division in this problem we automatically skip to multiplication

12 - 36 + 12

We answered 12 because 4 × 3 = 12

Our last steps in PEMDAS are addition and subtraction (A for addition and S for subtraction)

These are also interchangable, but both are apparent in this problem

Now it depends on location

Whichever sign (addition or subtraction) is first in accordance from left to right is where we start first)

Subtraction is first

-24 + 12

Now we add -24 + 12

-12

5 0

3 years ago

X and y=540 when X=10, find y when x=1/2

soldier1979 [14.2K]

Answer:

y = 27

Step-by-step explanation:

if x = 10 when y = 540 , y = 54x

if x = 1/2 y = 54*1/2 = 27

y = 27

4 0

3 years ago

169%of 705.8 how would u work that out

Verdich [7]

Answer:

'Percentage' is obtained by multiplying 705.8 by 169%.

169% × 705.8 =

(169 ÷ 100) × 705.8 =

(169 × 705.8) ÷ 100 =

119,280.2 ÷ 100 =

1,192.802 ≈

1,192.8;

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Find dy/dx for y= x^3 ln (cot x)

ICE Princess25 [194]

<h3>Answer</h3>

$\dfrac{dy}{dx} = 3x^2 \ln(\cot x)-x^3 \csc(x)\sec(x)$

<h3>Explanation</h3>

By the product rule $(d/dx)(f(x)g(x)) = f(x)g'(x) + g(x)f'(x)$ , we have

$\begin{aligned}\frac{dy}{dx} &= \left(x^3 \ln (\cot x) \right)' \\&= x^3\big(\ln (\cot x)\big)' + \ln (\cot x) \cdot \left(x^3\right)' \end{aligned}$

By the chain rule:

$\begin{aligned}\big(\ln (\cot x)\big)' &= \dfrac{1}{\cot x} \cdot (\cot x)' \\ &= \dfrac{1}{\cot x} \cdot -\csc^2 x\\&= -\tan (x) \csc^2(x) \\&= - \frac{\sin x}{\cos x} \cdot \frac{1}{\sin^2 x} = - \frac{1}{\cos x} \cdot \frac{1}{\sin x} \\&= -\csc(x)\sec(x)\end{aligned}$

By the power rule:

$(x^3)' = 3x^2$

thus

$\begin{aligned}\frac{dy}{dx} &= x^3\big(\ln (\cot x)\big)' + \ln (\cot x) \cdot \left(x^3\right)' \\&= x^3\big( -\csc(x)\sec(x) \big) + \ln(\cot x) \cdot (3x^2) \\&= -x^3 \csc(x)\sec(x) + 3x^2 \ln(\cot x) \\&= 3x^2 \ln(\cot x)-x^3 \csc(x)\sec(x)\end{aligned}$

Nothing to do to simplify any further, other than factoring out $x^2$ .

4 0

3 years ago

Please help please please

kap26 [50]

A. equation: p=$10.75h
variables=p(profit) h(hours)
B. use this equation and plug in 37 for h then solve.
hope this helps

8 0

2 years ago