A factory has three machines, A, B, and C, for producing items. Machine A makes 60% of all the widgets, and machine B makes the
rest. 3% of machine A’s widgets are defective, and 8% of machine B’s widgets are defective. One of the factory’s widgets is found to be defective; what is the probability that it was made by machine?
1 answer:
You might be interested in
This is supposed to be a question…????
Step-by-step explanation:
after you draw a unit circle you will find the answer
cosec(3pi)=1/sin(3pi)
sin3pi=sinpi=0
so cosec3pi=1/0 which is undefined.
Answer:
Step-by-step explanation:
0.32142857142
5 and 2/3 because 51/9= 5.666666667, which .66666667 in fraction form is 2/3
Letter B is the answer to your question