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andreev551 [17]
4 years ago
5

A factory has three machines, A, B, and C, for producing items. Machine A makes 60% of all the widgets, and machine B makes the

rest. 3% of machine A’s widgets are defective, and 8% of machine B’s widgets are defective. One of the factory’s widgets is found to be defective; what is the probability that it was made by machine?
Mathematics
1 answer:
Hoochie [10]4 years ago
6 0
Yes that’s is itttttty
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A triangle has side lengths of (1.2u+1.8v)(1.2u+1.8v) centimeters, (6.5u+8.7w)(6.5u+8.7w) centimeters, and (5.8w-6.9v)(5.8w−6.9v
Komok [63]

Answer:

7.7u - 5.1v + 14.5w

Step-by-step explanation:

Given length:

Side A = (1.2u+1.8v) centimeters,

Side B = (6.5u+8.7w) centimeters

Side C = (5.8w-6.9v) centimeters

Perimeter of a triangle = side A + side B + side C

= (1.2u+1.8v) + (6.5u+8.7w) + (5.8w-6.9v)

= 1.2u + 1.8v + 6.5u + 8.7w + 5.8w - 6.9v

Collect like terms

= 1.2u + 6.5u + 1.8v - 6.9v + 8.7w + 5.8w

= 7.7u - 5.1v + 14.5w

Therefore, the perimeter of the triangle is 7.7u - 5.1v + 14.5w

5 0
4 years ago
What is the equation of the line graphed below?
Vadim26 [7]

Answer:

A: y=6x+4

i hope this helps

4 0
3 years ago
(-9, -10) through the origin
Anit [1.1K]
So (x, y) and origin is is (0, 0) then you place three points on the graph, they should be as follows [(-9, -10), (0, 0), (9, 10)]. Count the spaces you moved from point a to point b, should be right 9 and up 10. meaning...
Slope = 9/10
I'm pretty sure this is correct, I hope this helped.
6 0
4 years ago
A set of normally distributed data has a mean of 3.2 and a standard deviation of 0.7. Find the probability of randomly selecting
jenyasd209 [6]

Answer:

P(Z> 3.13) = 0.000874

Step-by-step explanation:

A set of normally distributed data has a mean of 3.2 and a standard deviation of 0.7. Find the probability of randomly selecting 30 values and obtaining an average greater than 3.6.

We can denote the population mean with the symbol \mu

According to the information given, the data have a population mean:

\mu = 3.2.

The standard deviation of the data is:

\sigma = 0.7.

Then, from the data, a sample of size n = 30 is taken.

We want to obtain the probability that the sample mean is greater than 3.6

If we call

\mu_m to the sample mean then, we seek to find:

P(\mu_m> 3.6)

To find this probability we find the Z statistic.

Z = \frac{\mu_m-\mu}{\sigma_{\mu_m}}

Where:

Where \sigma_{\mu_m} is the standard deviation of the sample

\sigma_{\mu_m} = \frac{\sigma}{\sqrt{n}}

\sigma_{\mu_m} =\frac{0.7}{\sqrt{30}}\\\\\sigma_{\mu_m} = 0.1278

P(\frac{\mu_m-\mu}{\sigma_{\mu_m}}> \frac{3.6-3.2}{0.1278})

Then:

Z = \frac{3.6-3.2}{0.1278}\\\\Z = 3.13

The probability sought is: P(Z> 3.13)

When looking in the standard normal probability tables for right tail we obtain:

P(Z> 3.13) = 0.000874

8 0
3 years ago
What is the answer to this <br> (X-1)²-(x-1)
balu736 [363]

Answer:

x²-2x+1-x+1=x²-3x+2

3 0
3 years ago
Read 2 more answers
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