Let g (x)=x^2.what is the average rate of change of the function from x=4 to x=8?

Let U={x: x is an integer and 2≤x≤10}. In each of the following cases, find A,B and determine whether A⊆B,B⊆A, both or neither:

12345 [234]

A is not a subset of B but B is a subset of A (that is can be found in A) that is B⊆A is correct

<h3>Set theory</h3>

Set is defined as the arrangement of elements. They can be represented using the venn diagram.

Given the following sets

U = {x: x is an integer and 2≤x≤10} = {3, 4, 5, 6, 7, 8, 9}
A = {x: 2x+1>7} = {x > 3}

B={x: x^2>20} = {x >± 20}

From the set, can see that A is not a subset of B but B is a subset of A (that is can be found in A) that is B⊆A is correct

Learn more on sets here: brainly.com/question/13458417

8 0

2 years ago

Lindsay used two points x,y and x2, y2 to the equation of the line y= mx +b that passes through the points first she used the de

DiKsa [7]

Answer:

its A

Step-by-step explanation:

can pls have brainiest

4 0

3 years ago

Read 2 more answers

I need help solving this math problem, step by step and the answer (72/-2)^2

MaRussiya [10]

$( \frac{ - 72}{2} )^{2} \\ = \frac{ - 72 \times - 72}{2 \times 2} \\ = \frac{5184}{4} = 1296$

<h3>The answer is 1296.</h3>

6 0

3 years ago

Read 2 more answers

A data set includes data from student evaluations of courses. The summary statistics are nequals83, x overbarequals3.32, sequa

Andrews [41]

Answer:

Hypothesis

Null hypothesis: $\mu =3.50$

Alternative hypothesis: $\mu \neq 3.50$

Statistic

$t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928$

P value

The degrees of freedom are given by:

$df=n-1=83-1=82$

And the p value would be given by:

$p_v =2*P(t_{(82)}$

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

Step-by-step explanation:

Information given

$\bar X=3.32$ represent the sample mean

$s=0.56$ represent the sample deviation

$n=83$ sample size

$\mu_o =3.5$ represent the value to test

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true mean is equal to 3.5, the system of hypothesis are:

Null hypothesis: $\mu =3.50$

Alternative hypothesis: $\mu \neq 3.50$

Statistic

The statistic would be given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing we got:

$t=\frac{3.32-3.50}{\frac{0.56}{\sqrt{83}}}=-2.928$

P value

The degrees of freedom are given by:

$df=n-1=83-1=82$

And the p value would be given by:

$p_v =2*P(t_{(82)}$

Conclusion

Since the p value is lower than the significance level of 0.05 we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 3.5

8 0

3 years ago

3(2x+3)-4(3x-6)=16 show and explain.

STatiana [176]

Answer:

x = 17/6

Step-by-step explanation:

First of all remove parenthesis by using distribution

6x + 9 - 12x + 24 = 16

Then collect all like terms

-6x + 33 = 16

After that move the constant to the right

- 6x = 16 - 33

Calculate 16 - 33

-6x = -17

Divide both sides

x = 17/6

Hope this helps!

8 0

3 years ago