Solve for x over the real numbers:
x^3 (x^2 - 4) = 0
Split into two equations:
x^3 = 0 or x^2 - 4 = 0
Take cube roots of both sides:
x = 0 or x^2 - 4 = 0
Add 4 to both sides:
x = 0 or x^2 = 4
Take the square root of both sides:
Answer: x = 0 or x = 2 or x = -2
1) 3
2) 8
3)10
4)-4
Hope this helped
Answer: (m-21)(m+1)
Step-by-step explanation:
To factor this trinomial, find two numbers that multiply to -21 and add to -20:
(-21)(1)=-21
-21+1=-20
They are -21 and 1.
Add -21 and 1 to m to get both factors:
(m+(-21)) and (m+1)
(m-21) and (m+1)
Multiply them to get the answer:
(m-21)(m+1)
5/16 multiply the denominator by 2 and add 1 to the numerator
9/32 multiply the denominator by 4 and add 1 to the numerator
10/32 multiply the denominator by 4 and add 2 to the numerator
The answers is 96
Dont u just add?
