Answer: first option.
Step-by-step explanation:
You know that the height of the smaller cylinder is 6 cm and the height of the larger cylinder is 18 cm, then you can find the volume ratio. This is:
Knowing that the volume of the larger cylinder is 40,635 cubic centimeters, you need to multiply it by the volume ratio to find the volume of the smaller cylinder.
Therefore:
Answer:
270°
Step-by-step explanation:
(0, -1) is at the 270° angle. If you do a 360°, you end up back where you started, so the angle is still 270°.
Answer:
Substitute y=x-2y=x−2 into y=-0.5x+4y=−0.5x+4.
x-2=-0.5x+4x−2=−0.5x+4
2 Solve for xx in x-2=-0.5x+4x−2=−0.5x+4.
x=4x=4
3 Substitute x=4x=4 into y=x-2y=x−2.
y=2y=2
4 Therefore,
\begin{aligned}&x=4\\&y=2\end{aligned}
x=4
y=2
Step-by-step explanation:
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Step-by-step explanation:
The area would be 9 times compared to the area of the original square. To test this, you can let the side of the original square be equal 1. By tripling this side, the side becomes three. Utilizing the area of a square formula, A= s^2, the area of the original square would be 1 after substituting 1 for s. Then, you do the same for the area of the tripled square. With the substitution, the area of the tripled square would be 9. This result displays the area of the tripled square being 9 times as large as the area of the original square. This pattern can be used for other measurements of the square such as:
let s = 2, Original Area= 2^2 = 4 Tripled Area= (2(3))^2 = 6^2= 36. 36/4 = 9
let s = 3, Original Area = 3^2 = 9 Tripled Area - (3(3))^2 = 9^2 =81. 81/9 = 9
let s = 4, Original Area = 4^2 = 16 Tripled Area - (4(3))^2 = 12^2 = 144. 144/16 = 9
let s = 5, Original Area = 5^2 = 25 Tripled Area - (5(3))^2 = 15^2 = 225. 225/25 = 9
let s = 6, Original Area = 6^2 = 36 Tripled Area - (6(3))^2 = 18^2 = 324. 324/36 = 9
let s = 7, Original Area = 7^2 = 49 Tripled Area - (7(3))^2 = 21^2 = 2,401. 2,401/49 = 9
You can continue to increase the length of the square and follow this pattern and it will be consistent.
