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Natasha2012 [34]
3 years ago
6

I NEED THIS LITERALLY RIGHT NOW PLSSS HELP

Mathematics
2 answers:
astraxan [27]3 years ago
7 0

Answer:

its C 10/9

Step-by-step explanation:

s2008m [1.1K]3 years ago
4 0
Divide = multiply reciprocal
5/6 * 4/3 = 20/18 = 10/9
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On a coordinate plane, a square and a point are shown. The square has points R prime (negative 8, 1), S prime (negative 4, 1), T
VladimirAG [237]

Answer:

(–1, –6)

Step-by-step explanation:

Given that S(3, –5) was translated to S'(–4, 1), the transformation rule is (x-7, y+6). Then, the coordinates of square RSTU are:

R'(–8, 1) -> (-8+7, 1-6) -> R(-1, -5)

S'(–4, 1) -> (-4+7, 1-6) -> S(3, -5)

T'(–4, –3) -> (-4+7, -3-6) -> T(3, -9)

U'(–8, –3) -> (-8+7, -3-6) -> U(-1, -9)

The point (–1, –6) lies on the segment RU

7 0
3 years ago
Read 2 more answers
For which inequality is x = 5 a solution?<br>A x&lt;2<br>B. x&gt;9 <br>C x&lt;18 <br>D. x&gt; 42​
marishachu [46]

Answer:

c

Step-by-step explanation:

because 5 is smaller then 18

7 0
3 years ago
Select the correct answer. A report on Americans’ attitudes toward eating out found that 73% of the respondents to the survey up
LenaWriter [7]

Answer:

D

Step-by-step explanation:

Factors B, C and E are totally irrelevant.

8 0
4 years ago
Read 2 more answers
Suppose that $3000 is placed in an account that pays 16% interest compounded each year. Assume that no withdrawals are made from
Papessa [141]

Answer:

a) $3480

b) $4036.8

Step-by-step explanation:

The compound interest formula is given by:

A(t) = P(1 + \frac{r}{n})^{nt}

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

Suppose that $3000 is placed in an account that pays 16% interest compounded each year.

This means, respectively, that P = 3000, r = 0.16, n = 1

So

A(t) = P(1 + \frac{r}{n})^{nt}

A(t) = 3000(1 + \frac{0.16}{1})^{t}

A(t) = 3000(1.16)^{t}

(a) Find the amount in the account at the end of 1 year.

This is A(1).

A(t) = 3000(1.16)^{t}

A(1) = 3000(1.16)^{1} = 3480

(b) Find the amount in the account at the end of 2 years.

This is A(2).

A(2) = 3000(1.16)^{2} = 4036.8

4 0
3 years ago
Can someone help me?<br> (if you can show your work that would be nice).
lubasha [3.4K]

Answer:

1. x1=15.75.

2. 24/48=0.5

3. 24/25=0.96

Step-by-step explanation:

1. 15.75/18=0.875

2. you multiply 48 times 0.5 to find 24.

3. multiply 0.96 with 25 to get 24.

3 0
3 years ago
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