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qaws [65]
3 years ago
7

piston-cylinder assembly contains water vapor, initially at 10 bar and 360 degC. The water undergoes a process where pv=constant

until it reaches a final pressure of 1.5 bar. (a) Draw the process in p-v and T-s diagrams clearly labeling the states and the direction of the process. (b) Write the engineering model (c) Determine the energy transfers by work and heat, in kJ/kg and indicate their direction (in or out) (d) Determine the entropy production if the temperature at the boundary is Tb=630 K and comment on the nature of the process (reversible, irreversible, or impossible). (40 pts.)

Engineering
1 answer:
DIA [1.3K]3 years ago
3 0

Answer:

Check the explanation

Explanation:

A diagrams showing the process in p-v and T-s and the Model engineering <u><em>(which is the quest in constructing miniature working representations of proportionally-scaled in full-sized machines. It is a subdivision of metalworking with a sharp importance on artisanry, in contrast to mass production.)</em></u> can be seen in the attached images below.

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What’s the number of gold atoms in a nanogram? a picogram?
zvonat [6]

Answer :

The number of gold atoms in nanogram is, 3.057\times 10^{12}

The number of gold atoms in picogram is, 3.057\times 10^{9}

Explanation :

As we know that the molar mass of gold is, 196.97 g/mole. That means, 1 mole of gold has 196.97 grams of mass of gold.

As we know that,

1 mole contains 6.022\times 10^{23} number of atoms.

First we have to determine the number of gold atoms in a nanogram.

As, 196.97 grams of gold contains 6.022\times 10^{23} number of gold atoms

And, 1 grams of gold contains \frac{1g}{196.97g}\times (6.022\times 10^{23}) number of gold atoms

So, 10^{-9} nanograms of gold contains \frac{1g}{196.97g}\times (10^{-9})\times (6.022\times 10^{23})=3.057\times 10^{12} number of gold atoms

The number of gold atoms in nanogram is, 3.057\times 10^{12}

Now we have to determine the number of gold atoms in a picogram.

As, 196.97 grams of gold contains 6.022\times 10^{23} number of gold atoms

And, 1 grams of gold contains \frac{1g}{196.97g}\times (6.022\times 10^{23}) number of gold atoms

So, 10^{-12} picograms of gold contains \frac{1g}{196.97g}\times (10^{-12})\times (6.022\times 10^{23})=3.057\times 10^{9} number of gold atoms

The number of gold atoms in picogram is, 3.057\times 10^{9}

8 0
3 years ago
What is a jack plane used for​
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I hope this helps you :)

4 0
3 years ago
A point in the x-y plane is represented by its x-coordinate and y-coordinate. Design the class Point that can store and process
Black_prince [1.1K]

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

class pointType

{

public:

pointType()

{

x=0;

y=0;

}

pointType::pointType(double x,double y)

{

this->x = x;

this->y = y;

}          

void pointType::setPoint(double x,double y)

{

this->x=x;

this->y=y;

}

void pointType::print()

{

cout<<"("<<x<<","<<y<<")\n";

}

double pointType::getX()

{return x;

}

double pointType::getY()

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private:

   double x,y;

};

int main()

{

pointType p2;

double x,y;

cout<<"Enter an x Coordinate for point ";

cin>>x;

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return 0;

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5 0
3 years ago
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