Answer:
6 m²
Explanation:
application of fluid pressure according to Pascal's principle for the two pistons is given as:
Where P₁ is the pressure at the input and P₂ is the pressure at the output.
But P₁ = F₁ / A₁ and P₂ = F₂ / A₂
Where F₁ and F₂ are the forces applied at the input and output respectively and A₁ and A₂ are the area of the input pipe and output pipe respectively
Since,
But A₁ = 0.2 m², F₁ = 250 N, F₂ = 7500 N. Substituting values to get:
Therefore, the area of the pipe below the load is 6 m²
Answer:
Explanation:
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OSHA accepts the security codes of the state building To the degree that such codes comply with OSHA regulations, such as BOCA. All the codes and regulations for local, state-owned construction, electrical and life protection are under the same umbrella. Generally, all security protocols and specifications are in accordance with OSHA guidelines. Nonetheless, certain points will overlap, while localized codes will also be addressed to a particular community or state that may
Answer:
The average force F exherted by the nail over the hammer is 178.4 lbf.
Explanation:
The force F exherted by the nail over the hammer is defined as:
F = |I|/Δt
Where I and Δt are the magnitude of the impact and the period of time respectively. We know that the impact can be calculated as the difference in momentum:
I = ΔP = Pf - Pi
Where Pf and Pi are the momentum after and before the impact. Recalling for the definition for momentum:
P = m.v
Where m and v are the mass and the velocity of the body respectively. Notice that final hummer's momentum is zero due to the hammers de-acelerate to zero velocity. Then the momentum variation will be expressed as:
ΔP = - Pi = -m.vi
The initial velocity is given as 50 mph and we will expressed in ft/s:
vi = 50 mph * 1.47 ft/s/mph = 73.3 ft/s
By multiplyng by the mass of 1.8 lbs, we obtain the impulse I:
|I|= |ΔP|= |-m.vi| = 1.8 lb * 73.3 ft/s = 132 lb.ft/s
Dividing the impulse by a duration of 0.023 seconds, we finally find the force F:
F = 132 lb.ft/s / 0.023 s = 5740 lb.ft/s^2
Expressing in lbf:
F = 5740 lb.ft/s^2 * 0.031 lbf/lb.ft/s^2 = 178.4 lbf
Answer:
a) Final length of bar = 0.5 + 0.4838 *10^-3 = 0.5004838 M
b)Final Thickness = 6- -1.739 * 10^-3 mm = 5.998260mm\
c) % Reduction in area = (450-449.7391/450 ) = 0.58 %.
Explanation:
a) Change in length = Pl /AE = 90*1000*0.5*1000/75*207*6*10^3
= 0.4838mm Expansion.
Final length of bar = 0.5 + 0.4838 *10^-3 = 0.5004838 M
b )Change in width = - μpt/AE = -(0.3*90*1000*6/ 75*207*6*10^3)
= -1.739 * 10^-3 mm
Final Thickness = 6- -1.739 * 10^-3 mm = 5.998260mm
c )
New C/s area = 74.97827 *5.998260 = 449.7391 mm^2
% Reduction in area = (450-449.7391/450 ) = 0.58 %.
