Answer:
mechanical power used to overcome frictional effects in piping is 2.37 hp
Explanation:
given data
efficient pump = 80%
power input = 20 hp
rate = 1.5 ft³/s
free surface = 80 ft
solution
we use mechanical pumping power delivered to water is
.............1
put here value
= (0.80)(20)
= 16 hp
and
now we get change in the total mechanical energy of water is equal to the change in its potential energy
..............2
and that can be express as
..................3
so
......4
solve it we get
hp
so here
due to frictional effects, mechanical power lost in piping
we get here
put here value
= 16 -13.614
= 2.37 hp
so mechanical power used to overcome frictional effects in piping is 2.37 hp
Answer:
The average velocity is 0.203 m/s
Explanation:
Given;
initial displacement, x₁ = 20 yards = 18.288 m
final displacement, x₂ = ¹/₃ x 18.288 = 6.096 m
change in time between 5:02 PM and 5:03 PM, Δt = 3 mins - 2 mins = 1 min = 60 s
The average velocity is given by;
V = change in displacement / change in time
V = (x₂ - x₁) / Δt
V = (18.288 - 6.096) / 60
V = 0.203 m/s
Therefore, the average velocity is 0.203 m/s
Answer:
the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %
Explanation:
given data
pressure p1 = 1.4 MPa = 14 bar
temperature t1 = 32°C
exit pressure = 0.08 MPa = 0.8 bar
to find out
the quality of the refrigerant exiting the expansion valve
solution
we know here refrigerant undergoes at throtting process so
h1 = h2
so by table A 14 at p1 = 14 bar
t1 ≤ Tsat
so we use equation here that is
h1 = hf(t1) = 332.17 kJ/kg
this value we get from table A13
so as h1 = h2
h1 = h(f2) + x(2) * h(fg2)
so
exit quality = 
exit quality = 
so exit quality = 0.2337 = 23.37 %
the quality of the refrigerant exiting the expansion valve is 0.2337 = 23.37 %