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vaieri [72.5K]
3 years ago
15

Heats of Reaction and Hess's Law experiment tells you to look up three values. Write down these values. Be sure to clearly indic

ate which value you are typing. Be sure to include units and to use joule based units (i.e. joules/mol or kJoules/mole).
Engineering
1 answer:
Anna [14]3 years ago
8 0

Answer:

Enthalpy of reaction (kJoules/mole)

Heat of formation of products (kJoules/mole)

Heat of reaction of reactants (kJoules/mole)

Explanation:

The general expression for calculating the overall enthalpy of reaction is given as following:

ΔH = ∑ΔH[producst] - ∑Δ[reactants]

Thus, the heat of reaction is given as the difference between the formation of the products and the formation of the reactants. The units are expressed as kJ/mol of reactants or products.

Thus, the three values are fundamental in the determination of the overall energy of the reaction from Hess' Law.

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Answer:

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Explanation:

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3 years ago
In Illinois, once a person has obtained their boating education certificate what is the minimum age to operate a motorized vesse
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Answer:

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3 years ago
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Since the engineering design process may take the engineer back to its beginning, the process is considered ________
Valentin [98]

Answer:

Cyclical

Explanation:

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7 0
3 years ago
The following are the results of a sieve analysis. U.S. sieve no. Mass of soil retained (g) 4 0 10 18.5 20 53.2 40 90.5 60 81.8
il63 [147K]

Answer:

a.)

US Sieve no.                         % finer (C₅ )

4                                                  100

10                                                95.61

20                                               82.98

40                                               61.50

60                                               42.08

100                                              20.19

200                                              6.3

Pan                                               0

b.) D10 = 0.12, D30 = 0.22, and D60 = 0.4

c.) Cu = 3.33

d.) Cc = 1

Explanation:

As given ,

US Sieve no.             Mass of soil retained (C₂ )

4                                            0

10                                          18.5

20                                         53.2

40                                         90.5

60                                         81.8

100                                        92.2

200                                       58.5

Pan                                        26.5

Now,

Total weight of the soil = w = 0 + 18.5 + 53.2 + 90.5 + 81.8 + 92.2 + 58.5 + 26.5 = 421.2 g

⇒ w = 421.2 g

As we know that ,

% Retained = C₃ = C₂×\frac{100}{w}

∴ we get

US Sieve no.               % retained (C₃ )               Cummulative % retained (C₄)

4                                            0                                           0

10                                          4.39                                      4.39

20                                         12.63                                     17.02

40                                         21.48                                     38.50

60                                         19.42                                     57.92

100                                        21.89                                     79.81

200                                       13.89                                     93.70

Pan                                        6.30                                      100

Now,

% finer = C₅ = 100 - C₄

∴ we get

US Sieve no.               Cummulative % retained (C₄)          % finer (C₅ )

4                                                     0                                          100

10                                                  4.39                                      95.61

20                                                 17.02                                     82.98

40                                                 38.50                                    61.50

60                                                 57.92                                    42.08

100                                                79.81                                     20.19

200                                                93.70                                   6.3

Pan                                                 100                                        0

The grain-size distribution is :

b.)

From the diagram , we can see that

D10 = 0.12

D30 = 0.22

D60 = 0.12

c.)

Uniformity Coefficient = Cu = \frac{D60}{D10}

⇒ Cu = \frac{0.4}{0.12} = 3.33

d.)

Coefficient of Graduation = Cc = \frac{D30^{2}}{D10 . D60}

⇒ Cc = \frac{0.22^{2}}{(0.4) . (0.12)} = 1

3 0
3 years ago
What is the difference between a discrete and continuous system?
Serjik [45]

Answer:Discrete system are those system which change the state at the discrete point of time and continuous system are those which have state change at continuous period of time.

Explanation:

  • The major difference between discrete and continuous system is that, discrete system has state change over a discontinuous time period whereas the change of state in continuous system is over a continuous time period .
  • Variations can be found in the discrete system signal but  in continuous system variation cannot be found input and output signal.
  • Example:-

       Discrete system:-employees reporting at office at different time like

       9:10am, 9:15am etc              

       <u> Continuous system</u>:-the water flow over a dam in particular quantity                    

7 0
3 years ago
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