Five times x plus seven equals eighteen
9x^2-16y^2=
(3x+4y)(3x-4y)
The answer is a = 3/4 = 0.75
First get rid of the paranthesis,

Then set the denominators equal:

Then remove the denominators and solve:

Eliminate -12a^2 by adding 12a^2 to both sides:

Take the fourth root of them or take the square root twice:
![\sqrt[4]{256 {a}^{4} } = \sqrt[4]{81} \\ 4a = 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B256%20%7Ba%7D%5E%7B4%7D%20%7D%20%20%3D%20%20%5Csqrt%5B4%5D%7B81%7D%20%20%20%5C%5C%20%204a%20%3D%203)
Divide both sides by 4:
Step-by-step explanation:
First we have to same the bases.
As we know 8=2^3.
Replace 8 with 2^3.
Like this .
2^3x=2^3(2x+1).
Now 3x=3(2x+1) distribute 3 by the Barker.
3x=6x+3.
6x+3=3x.
6x-3x=-3.
3x=-3.
X=-1.