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Reil [10]
3 years ago
9

Ayshays new bike has 26 inch diameter wheels. What is the circumference of her new wheel? Give your answer correct to 1 decimal

place.
Mathematics
1 answer:
tatuchka [14]3 years ago
6 0

Answer:

87.96 will be 88.0

Step-by-step explanation:

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3 years ago
If $18\sqrt 8-8\sqrt{18}=\sqrt n, what is n?
Ksivusya [100]

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288 trust me it is 100% right I tried it as an answer an got it right.

Step-by-step explanation:

4 0
3 years ago
What is .74 repeating as a fraction?
Sedaia [141]
The answer to your question is 74/99:D
8 0
3 years ago
Drag the labels to the correct locations on the table. Each label can be used more than once.
Julli [10]

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first one linear

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linear

Step-by-step explanation:

6 0
3 years ago
A recent estimate by a large distributor of gasoline claims that 60% of all cars stopping at their service stations chose unlead
Anton [14]

Answer:

We reject the null hypothesis and conclude that at least 2 proportions differ from the stated value.

Step-by-step explanation:

There are 3 types of gas listed in the question.

Thus;

n = 3

DF = n - 1

DF = 3 - 1

DF = 2

Let's state the hypotheses;

Null hypothesis; H0: P_regular = P_super unleaded = 20%; P_i leaded = 60%

Alternative hypothesis; Ha: At least 2 proportions differ from the stated value.

Observed values are;

Regular gas; O = 51

Unleaded gas; O = 261

Super Unleaded; O = 88

Total observed values = 51 + 261 + 88 = 400

We are told that super unleaded and regular were each selected 20% of the time and that unleaded gas was chosen 60% of the time.

Thus, expected values are;

Regular gas; E = 20% × 400 = 80

Unleaded gas; E = 60% × 400 = 240

Super Unleaded; E = 20% × 400 = 80

Formula for chi Square goodness of fit is;

X² = Σ[(O - E)²/E]

X² = (51 - 80)²/80) + (261 - 240)²/240) + (88 - 80)²/80)

X² = 13.15

From the chi Square distribution table attached and using; DF = 2 and X² = 13.15, we can trace the p-value to be approximately 0.001

Also from online p-value from chi Square calculator attached, we have p to be approximately 0.001 which is similar to what we got from the table.

Now, if we take the significance level to be 0.05, it means the p-value is less than it and thus we reject the null hypothesis and conclude that at least 2 proportions differ from the stated value.

4 0
3 years ago
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