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Reil [10]
3 years ago
9

Ayshays new bike has 26 inch diameter wheels. What is the circumference of her new wheel? Give your answer correct to 1 decimal

place.
Mathematics
1 answer:
tatuchka [14]3 years ago
6 0

Answer:

87.96 will be 88.0

Step-by-step explanation:

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A 2-column table with 3 rows titled Units of Length. Column 1 is labeled Customary System Units with entries 1 inch, 1 foot, 1 m
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Answer:

the answer is b

Step-by-step explanation:

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3 years ago
A bird traveled 4 miles north before stopping to rest. The bird then flew 2,640 yards south in search of food. Finally, it flew
ra1l [238]
7 and 1/2 mile because 2,640=1.5 miles
4-1.5=2.5+5=7.5
8 0
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Adalyn earns $42 for mowing lawns for 6 hours. If Adalyn charges at the same rate, how many hours will it takes her to earn $63
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2 hours is how long it would take
5 0
3 years ago
Read 2 more answers
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
What is the solution to this equation?
Morgarella [4.7K]

Answer:

6(x - 3) = 3x  + 9 \\  \\ 6x - 18 = 3x + 9 \\  \\ 6x - 3x = 18 + 9 \\  \\ 3x = 27 \\  \\ x  = \frac{27}{3}  \\  \\ x = 9

<h3>Option A</h3>
7 0
3 years ago
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