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Vsevolod [243]
3 years ago
14

) A bin contains 60 light bulbs of which 5 are defective. If 4 light bulbs are randomly selected from the bin with replacement,

find the probability that all the bulbs selected are good ones. Round to the nearest thousandth if necessary
Mathematics
1 answer:
8090 [49]3 years ago
3 0

Answer:

0.706

Step-by-step explanation:

In this question, we are asked to calculate the probability that if 4 light bulbs are selected out of a total of 60, with 5 defective ones, all are good.

Firstly we need to find the probability of selecting a bulb that is not defective. Let’s call this P(g).

Since 5 are defective, it means 60-5 = 55 bulbs are not defective.

The probability of selecting a bulb not defective would be 55/60 = 11/12

Now, four are selected with claims that non are defective, the probability here would thus be 11/12 * 11/12 * 11/12 * 11/12 = 0.706066743827

To the nearest thousandth, we have 0.706

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Answer:

0.81 = 81% probability that a randomly selected student is taking a math class or an English class.

0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

Step-by-step explanation:

We solve this question working with the probabilities as Venn sets.

I am going to say that:

Event A: Taking a math class.

Event B: Taking an English class.

77% of students are taking a math class

This means that P(A) = 0.77

74% of student are taking an English class

This means that P(B) = 0.74

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This means that P(A \cap B) = 0.7

Find the probability that a randomly selected student is taking a math class or an English class.

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P(A \cup B) = P(A) + P(B) - P(A \cap B)

So

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0.19 = 19% probability that a randomly selected student is taking neither a math class nor an English class

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