Question

Find a and b if the points p(6,0) and q(3,2) lie on the graph of ax + by =12

Answer 1

Answer:

$a= 2$

$b = 3$

Step-by-step explanation:

Given

$p(x,y) = (6,0)$

$q(x,y) = (3,2)$

$ax + by = 12$

Required

Find a and b

In $p(x,y) = (6,0)$, $x = 6$ and $y = 0.$

This gives:

$a*6 + b*0 = 12$

$6a = 12$

Divide by 6

$a= 2$

In $q(x,y) = (3,2)$. $x = 3$ and $y = 2.$

This gives:

$a*3 + b*2 = 12$

$3a + 2b = 12$

Substitute 2 for a

$3*2 + 2b = 12$

$6 + 2b = 12$

Collect Like Terms

$2b = 12 - 6$

$2b = 6$

Divide by 2

$b = 3$