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3 years ago

Please help me on this question

Mathematics

2 answers:

just olya [345]3 years ago

8 0

130.2 is the answer ✌130.2

AleksandrR [38]3 years ago

7 0

Answer:

The area can be expressed as: $\pi r^2+lw$ .

We have l=10, because 18-2(4)

We have w=8, as given.

Thus, the rectangle area is 80.

There are two semicircles, but they add to form a full circle, which makes things a lot easier. We have the circle area formula, and substituting the values gives us 50.24 as the circle volume

80+50.24=130.24.

Rounded to 1 decimal place that is 130.2

Hope this helps :)

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How do you calculate the area and the perimeter of a parallelogram and a triangle?

Mnenie [13.5K]

for parallelograms:

area = b(h)

so basically, the length times the height. just like how you would find the area of a square.

perimeter: just add all of the sides together.

for triangles:

area = 1/2(b) x h

so half the length multiplied by the height. for example, if the length was 4, you have to use half of that. so that means 2 times whatever the height is.

perimeter: again, just add all three sides together

7 0

3 years ago

Read 2 more answers

The map of a walking trail is drawn a coordinate grid with three points of interest. The trail starts at R(-3,2) and goes to S(2

Nezavi [6.7K]

Answer:

12 units

Step-by-step explanation:

Given that :

R(-3,2)

S(2,2)

T(2,-5).

The total length ;

Distance between two points : √[(x2 - x1)² + (y2 - y1)²]

Distance between R and S :

R = (-3,2)

S(2,2)

√[((2 - (-3))^2 + (2 - 2)^2]

Sqrt(5^2 + 0^2)

D1 = 5 units

Distance between S and T:

S(2,2)

T(2,-5).

D2 = √[(2 - 2)^2 + (-5 - 2)^2]

D2 = sqrt(0^2 + (-7)^2)

D2 = 7 units

Hence, total length = D1 + D2 = (5 + 7) = 12 units

5 0

2 years ago

the price of an item has increased 15% since last year. However l a person can buy the item for a 25%employee discount. The empl

Fiesta28 [93]

Let us assume last year the price of the item = $x.

After increase in price by 15% the new price = x + 15% of x = x+ 0.15x = 1.15x.

There is a 25% discount for employee.

25% of 1.15x = 0.25 × 1.15x = 0.2875 x.

Price after discount = 1.15x - 0.2875 x = 0.8625x.

The employee pays $172.50.

Therefore,

0.8625x = 172.50.

Dividing both sides by 0.08625.

$\frac{0.8625x }{ 0.8625} =\frac{172.50}{0.8625}$

<h3>x=200.</h3><h3>Therefore, last year the price was $200.</h3>

8 0

3 years ago

A random experiment was conducted where a Person A tossed five coins and recorded the number of ""heads"". Person B rolled two d

cestrela7 [59]

Answer:

(10) Person B

(11) Person B

(12) $P(5\ or\ 6) = 60\%$

(13) Person B

Step-by-step explanation:

Given

Person A $\to$ 5 coins (records the outcome of Heads)

Person $\to$ Rolls 2 dice (recorded the larger number)

Person A

First, we list out the sample space of roll of 5 coins (It is too long, so I added it as an attachment)

Next, we list out all number of heads in each roll (sorted)

$Head = \{5,4,4,4,4,4,3,3,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2,2,2,1,1,1,1,1,0\}$

$n(Head) = 32$

Person B

First, we list out the sample space of toss of 2 coins (It is too long, so I added it as an attachment)

Next, we list out the highest in each toss (sorted)

$Dice = \{2,2,3,3,3,3,4,4,4,4,4,4,5,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,6\}$

$n(Dice) = 30$

Question 10: Who is likely to get number 5

From person A list of outcomes, the proportion of 5 is:

$Pr(5) = \frac{n(5)}{n(Head)}$

$Pr(5) = \frac{1}{32}$

$Pr(5) = 0.03125$

From person B list of outcomes, the proportion of 5 is:

$Pr(5) = \frac{n(5)}{n(Dice)}$

$Pr(5) = \frac{8}{30}$

$Pr(5) = 0.267$

<em>From the above calculations: </em> $0.267 > 0.03125$ <em> Hence, person B is more likely to get 5</em>

Question 11: Person with Higher median

For person A

$Median = \frac{n(Head) + 1}{2}th$

$Median = \frac{32 + 1}{2}th$

$Median = \frac{33}{2}th$

$Median = 16.5th$

This means that the median is the mean of the 16th and the 17th item

So,

$Median = \frac{3+2}{2}$

$Median = \frac{5}{2}$

$Median = 2.5$

For person B

$Median = \frac{n(Dice) + 1}{2}th$

$Median = \frac{30 + 1}{2}th$

$Median = \frac{31}{2}th$

$Median = 15.5th$

This means that the median is the mean of the 15th and the 16th item. So,

$Median = \frac{5+5}{2}$

$Median = \frac{10}{2}$

$Median = 5$

<em>Person B has a greater median of 5</em>

Question 12: Probability that B gets 5 or 6

This is calculated as:

$P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}$

From the sample space of person B, we have:

$n(5\ or\ 6) =n(5) + n(6)$

$n(5\ or\ 6) =8+10$

$n(5\ or\ 6) = 18$

So, we have:

$P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}$

$P(5\ or\ 6) = \frac{18}{30}$

$P(5\ or\ 6) = 0.60$

$P(5\ or\ 6) = 60\%$

Question 13: Person with higher probability of 3 or more

Person A

$n(3\ or\ more) = 16$

So:

$P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Head)}$

$P(3\ or\ more) = \frac{16}{32}$

$P(3\ or\ more) = 0.50$

$P(3\ or\ more) = 50\%$

Person B

$n(3\ or\ more) = 28$

So:

$P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Dice)}$

$P(3\ or\ more) = \frac{28}{30}$

$P(3\ or\ more) = 0.933$

$P(3\ or\ more) = 93.3\%$

By comparison:

$93.3\% > 50\%$

Hence, person B has a higher probability of 3 or more

7 0

2 years ago

T = WP [ M² - ( M-S)² ]

QveST [7]

Answer:

W PM^2 − WP(M−S)^2=T

Step-by-step explanation:

this is what mathaway said

8 0

3 years ago