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3 years ago

Here is a set of data:1300, 18, 25, 19, -7, 24. which observation is the outlier

1 answer:

8 0

An outlier is a point which falls more that 1.5 times the interquartile range above the thrid quartile or below the first quartile. It is basically the point which is abnormally off the limit within which other points are within. Given our data points:
1300, 18,25,18,-7,24
compared to the rest of the points, 1300 is quite of the limit. Thus;
Answer: 1300

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What is the area of this composite shape?

grandymaker [24]

(29-22)*26+(26-21)*22

Cut the figure into 2 then find the unknown lengths to find each part. Add them together, and you'll get the answer.

4 0

3 years ago

Find, correct to the nearest degree, the three angles of the triangle with the given vertices.

Leokris [45]

Answer:

angle CAB = 113.8 degree

angle ABC = 35.6 degree

angle BCA = 30.6 degree

Step-by-step explanation:

Given data:

A(1, 0, −1),

B(5, −3, 0),

C(1, 5, 2)

calculate the length of side by using the distance formula

AB = (5,-3,0) - (1,0,-1) = (4,-3,1)

AC= (1,5,2) - (1,0,-1) = (0,5,3)

|AB|

|AC| = $\sqrt {(0 + 5^2+3^2)} = \sqrt{34}$

From following formula, calculate the angle between the two side i.e Ab and AC

AB.AC = |AB|*|AC| cos ∠CAB

(4,-3,1).(0,5,3)

4*0 -3*5 +1*3

-12 =

cos ∠CAB = - 0.404

angle CAB = 113.8 degree

BA =B- A = (1,0,-1) - (5,-3,0) = (-4,3,-1)

BC = (1,5,2)-(5,-3,0) = (-4,8,2)

|BA| = \sqrt{(26)}

|BC| $= \sqrt {(4^2 + 8^2 + 2^2)} = \sqrt{(84)}$

BA.BC = |BA|*|BC|* cosABC

(-4,3,-1).(-4,8,2) = $\sqrt{(26)} * \sqrt{(84)} *cosABC$

16+24-2

cos ∠ABC = 0.813

angle ABC = 35.6 degree

we know sum of three angle in a traingle is 180 degree hence

sum of all three angle = 180

angle BCA + 35.6 + 113.8 = 180

angle BCA = 30.6 degree

7 0

3 years ago

Can someone help me with this? I'm really confused. Im supposed to be doing a projet, but i don't know how to do it

mr_godi [17]

Answer:

Step-by-step explanation:

the image isnt showing

5 0

2 years ago

Use the data set to answer the question. {22,26,28,35,45,63,91} What is the mean absolute deviation (MAD) of the data set? Enter

shtirl [24]

Answer:

mean absolute deviation is 18.85

Step-by-step explanation:

<u>Step 1:</u>-

Given observation values 22,26,28,35,45,63,91

$mean (x ) = \frac{22+26+28+35+45+63+91}{7}$

mean = 44.28≅ 44

<u>Step2</u>:-

The deviations of the respective observations from the mean (x)

That is $x_{i}-x$

22-44, 26-44,28-44,35-44,45-44,63-44,91-44

-22, -18 ,-16 ,-9, 1, 19, 47

<u>Step 3:</u>-

The absolute values of the given data

$x_{i}-x$

modulus of all these values

22,18,16,9.1,19,47

<u>Step 4</u>:-

Mean absolute deviation M.D=∑ $\frac{x_{i} - x }{n}$

$MAD = \frac{22+18+16+9+1+19+47}{7}$

on simplification we get mean absolute deviation is 18.85

6 0

2 years ago

Helpppppppppp meeeeeeeeee pllzzzzzzzzz

Fantom [35]

Using the binomial distribution, it is found that there is a 0.7447 = 74.47% probability that fewer than 7 of them show up.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem, the values of the parameters are given as follows:

p = 0.7, n = 8.

The probability that fewer than 7 of them show up is given by:

[tec]P(X < 7) = 1 - P(X \geq 7)[/tex]

In which:

$P(X \geq 7) = P(X = 7) + P(X = 8)$

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{8,7}.(0.7)^{7}.(0.3)^{1} = 0.1977$

$P(X = 8) = C_{8,8}.(0.7)^{8}.(0.3)^{0} = 0.0576$

Then:

$P(X \geq 7) = P(X = 7) + P(X = 8) = 0.1977 + 0.0576 = 0.2553$

[tec]P(X < 7) = 1 - P(X \geq 7) = 1 - 0.2553 = 0.7447[/tex]

0.7447 = 74.47% probability that fewer than 7 of them show up.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

8 0

2 years ago