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3 years ago

Explain how you can use the graph of the quadratic function f(x) to solve the equation f(x)=0

1 answer:

6 0

F(x)=0
f(x)=y
so where y=0, the x value is the x in f(x)
basically, where the line crosses or touches the x axis, those ar the x values that make the function true

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Simplify the expression.<br><br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B1%2B%5Csqrt%7B3%7D%20%7D" id="TexFormula1" t

REY [17]

Answer:

Step-by-step explanation:

Rationalize the denominator by multiplying both denominator & numerator by the conjugate of the denominator.

Conjugate of the denominator 1 + √3 is 1 - √3

$\frac{6}{1+\sqrt{3}}=\frac{6(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\=\frac{6(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\=\frac{6(1-\sqrt{3})}{1^{2}-(\sqrt{3})^{2}}\\\\=\frac{6(1-\sqrt{3})}{1-3}\\\\=\frac{6(1-\sqrt{3})}{-2}\\\\=(-3)(1-\sqrt{3})\\\\=-3+3\sqrt{3}$

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3 years ago

Of a classroom filled with 20 students, 2 will be selected to stay after school and correct homework for extra credit. How

Tcecarenko [31]

Answer: 10

Step-by-step explanation:

20/2=10

pairs of two

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3 years ago

Read 2 more answers

Find the domain: y= 6+9x 6− x−1

inna [77]

Answer:

Domain = {All real values of x EXCEPT x = -5 and x = 7}

Step-by-step explanation:

This is a rational function given as y=\frac{6+9x}{6-|x-1|}y=

6−∣x−1∣

6+9x

The domain is the set of all real value of x for which the function is defined.

For rational functions, we need to find which value of x makes the denominator equal to 0. We need to exclude those values from the domain.

Now

6 - |x-1| = 0

|x-1| = 6

x- 1 = 6

-(x-1) = 6

x = 6+1 = 7

and

-x+1=6

x = 1-6 = -5

So, the x values of -5 and 7 makes this function undefined. So the domain is the set of all real numbers except x = -5 and x = 7

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3 years ago

Which one of the following is always true?a. The coefficient of variation measures variability in a positively skewed data set r

Tom [10]

Answer:

C. The coefficient of variation is a measure of relative dispersion that expresses the standard deviation as a percentage of the mean, for any data on a ratio scale and an interval scale

Step-by-step explanation:

Th Coefficient of Variance is a measure of dispersion that can be calculated using the formula:

$CV = \frac{\sigma_{x} }{\mu_{x} } * 100%$

Where $\sigma{x}$ is the Standard Deviation

and $\mu_{x}$ is the sample mean

From the formula written above, it is shown that the Coefficient of Variation expresses the Standard Deviation as a percentage of the mean.

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