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docker41 [41]
3 years ago
14

Difference between rest and motion​

Physics
2 answers:
andre [41]3 years ago
8 0

Answer:

Rest- IT IS THE STATE IN WHICH BODY DON'T MOVE FROM ITS PLACE.

Motion-IT IS THE STATE IN WHICH BODY MOVES FROM ITS PLACE.

Ivan3 years ago
6 0

Explanation:

A body is said to be at rest if doesn't change it's position with respect to its surroundings while a body is said to be in motion if it continuously changes it's position with respect to its surroundings.

Motion : If an object change its position with respect to time and surroundings, it is said to be in motion .

For example: If we stand on a road and observe a moving car , we will findo that it's position is continuously changing with respect to us and different time intervals . So the car is in motion

Rest: We can say that a body is at rest , if it does not change its position with respect to time and it's surroundings .

For example: a standing tree remain fixed in its place if you see it at different times intervals . So , it is said to be in the state of rest.

Rest and motion are relative terms : when we say that a body is at rest , first we consider that the earth is at rest . But, actually the earth itself is constantly rotating on it's own axis . So ,everything on the earth is also in motion.

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The equation below is for potassium oxide.
ValentinkaMS [17]

Answer: The ratio of atoms of potassium to ratio of atoms of oxygen is 4:2

Explanation:

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5 0
3 years ago
Read 2 more answers
A ball is thrown vertically downwards with a speed 7.3 m/s from the top of a 51 m tall building. With what speed will it hit the
ddd [48]

Answer:

32.46m/s

Explanation:

Hello,

To solve this exercise we must be clear that the ball moves with constant acceleration with the value of gravity = 9.81m / S ^ 2

A body that moves with constant acceleration means that it moves in "a uniformly accelerated motion", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are the follow

\frac {Vf^{2}-Vo^2}{2.a} =X

Where

Vf = final speed

Vo = Initial speed =7.3m/S

A = g=acceleration =9.81m/s^2

X = displacement =51m}

solving for Vf

Vf=\sqrt{Vo^2+2gX}\\Vf=\sqrt{7.3^2+2(9.81)(51)}=32.46m/s

the speed with the ball hits the ground is 32.46m/s

8 0
3 years ago
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