Answer:
![\rho = 3.68 *10^{-8} Ω. m](https://tex.z-dn.net/?f=%5Crho%20%3D%203.68%20%2A10%5E%7B-8%7D%20%CE%A9.%20m)
Explanation:
The resistance is given as
![R = \frac{\rho L}{A}](https://tex.z-dn.net/?f=R%20%3D%20%5Cfrac%7B%5Crho%20L%7D%7BA%7D)
Where A IS Cross sectional area of wire![= \pi r^{2}](https://tex.z-dn.net/?f=%3D%20%5Cpi%20r%5E%7B2%7D)
therefore resistivity \rho can be wrtten as
![\rho = \frac{\pi Rd^{2}}{4L}](https://tex.z-dn.net/?f=%5Crho%20%3D%20%5Cfrac%7B%5Cpi%20Rd%5E%7B2%7D%7D%7B4L%7D)
Putting all value to get resistivity value![\rho =\frac{\pi* 61*10^{-3}* (1.33*10^{-3})^{2}}{4*2.3}](https://tex.z-dn.net/?f=%5Crho%20%3D%5Cfrac%7B%5Cpi%2A%2061%2A10%5E%7B-3%7D%2A%20%281.33%2A10%5E%7B-3%7D%29%5E%7B2%7D%7D%7B4%2A2.3%7D)
![\rho = 3.68 *10^{-8} Ω. m](https://tex.z-dn.net/?f=%5Crho%20%3D%203.68%20%2A10%5E%7B-8%7D%20%CE%A9.%20m)
Answer:
The value is
Explanation:
From the question we are told that
The distance of friends house from your point is ![a = 10 \ km](https://tex.z-dn.net/?f=a%20%3D%20%2010%20%5C%20%20km)
The distance of your friends street from your street is ![b = 6 \ km \ in the \ direction \ towards \ the \ north](https://tex.z-dn.net/?f=b%20%3D%20%206%20%5C%20%20km%20%5C%20%20in%20the%20%5C%20direction%20%5C%20%20towards%20%5C%20%20the%20%20%5C%20%20north)
The diagram illustrating this question is shown on the first uploaded image
From the diagram we can apply by Pythagoras theorem as follows
![a^2 = b^2 + c^2](https://tex.z-dn.net/?f=a%5E2%20%3D%20%20b%5E2%20%2B%20%20c%5E2)
=>
=>
=>
Answer:
<h2>3.36J</h2>
Explanation:
Step one:
given data
mass m= 1.3kg
distance moved s= 2.8m
opposing frictional force= 0.34N
assume g= 9.81m/s^2
we know that work done= force *distance moved
1. work done to push the book= 1.55*2.8=4.34J
2. Work against friction = force of friction x distance
= 0.34*2.8=0.952J
Step two:
the work done on the book is the net work, which is
Network done= work done to push the book- Work against friction
Network done= 4.32-0.952=3.36J
<u>Therefore the work of the 1.55N 3.36J</u>
Answer:
C. 85%
Explanation:
A cylinder fitted with a piston exists in a high-pressure chamber (3 atm) with an initial volume of 1 L. If a sufficient quantity of a hydrocarbon material is combusted inside the cylinder to produce 1 kJ of energy, and if the volume of the chamber then increases to 1.5 L, what percent of the fuel's energy was lost to friction and heat?
A. 15%
B. 30%
C. 85%
D. 100%
work done by the system will be
W=PdV
p=pressure
dV=change in volume
3tam will be changed to N/m^2
3*1.01*10^5
W=3.03*10^5*(1.5-1)
convert 0.5L to m^3
5*10^-4
W=3.03*10^5*5*10^-4
W=152J
therefore
to find the percentage used
152/1000*100
15%
100%-15%
85% uf the fuel's energy was lost to friction and heat