Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
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Answer: 1</h3>
Explanation:
The original expression is the same as 
since 
The degree of any polynomial is always the largest exponent. This applies to single variable polynomials only.
Therefore, the degree of is 1. This is a linear polynomial, and it's also a binomial since it has 2 terms 17x and 4.
Answer: .458 or about .46 cents if you round to the nearest cent
Step-by-step explanation:Since the price for 5 pounds of potatoes is 2.29 all together you can divide 2.29 by 5 which gives you the price for one pound of potatoes. Since one pound of potatoes would be the unit price. Hope this helps :D
(1.2×10^2) + (3.04×10^5)
They must be to the same power to add
3.04 *10^5 to change to the 2nd power (5-2=3) move the decimal 3 places to the right = 3040. * 10^2
1.2 * 10^2 + 3040 *10^2=
add the numbers keep the exponents the same
3041.2 * 10^2
there can only be 1 number before the decimal in scientific notation so we need to move the decimal 3 places to the left, which adds 3 to the exponent
3.0412 * 10 ^ (2+3)
3.0412 * 10^5
Divide 42 by 4 for one fourth. Divide 13.5 by 5 and multiply that by 2.
