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Natasha2012 [34]
3 years ago
14

333 erasers cost \$4.41$4.41dollar sign, 4, point, 41. Which equation would help determine the cost of 444 erasers? Choose 1 ans

wer: Choose 1 answer: (Choice A) A \dfrac{4}{x} = \dfrac{\$4.41}{3} x 4 ​ = 3 $4.41 ​ start fraction, 4, divided by, x, end fraction, equals, start fraction, dollar sign, 4, point, 41, divided by, 3, end fraction (Choice B) B \dfrac{4}{\$4.41} = \dfrac{x}{3} $4.41 4 ​ = 3 x ​ start fraction, 4, divided by, dollar sign, 4, point, 41, end fraction, equals, start fraction, x, divided by, 3, end fraction (Choice C) C \dfrac{4}{3} = \dfrac{\$4.41}{x} 3 4 ​ = x $4.41 ​ start fraction, 4, divided by, 3, end fraction, equals, start fraction, dollar sign, 4, point, 41, divided by, x, end fraction (Choice D) D \dfrac{4}{x} = \dfrac{3}{\$4.41} x 4 ​ = $4.41 3 ​ start fraction, 4, divided by, x, end fraction, equals, start fraction, 3, divided by, dollar sign, 4, point, 41, end fraction (Choice E) E None of the above
Mathematics
1 answer:
Rudiy273 years ago
6 0

Answer:

Option D will be correct.

Step-by-step explanation:

The 333 erasers cost $4.41.

We have to determine the cost of 444 erasers.

Let the price of 444 erasers is $x.

Therefore, since the number of erasers cost per dollars is constant, hence the equation that would help to determine the cost of 444 erasers will be \frac{333}{4.41} = \frac{444}{x}

⇒ \frac{3}{4.41} = \frac{4}{x}

Therefore, option D will be correct. (Answer)

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Answer:

Erik's average speed exceeds the speed limit by 6.91 miles per hour.

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Let suppose that Erik travels at constant speed. Hence, the speed (v), measured in miles per hour, is determined by following equation of motion:

v = \frac{s}{t} (1)

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6 0
3 years ago
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8 0
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5. Two vertices of a rectangle are (8,-5) and (8,7). If the area of the rectangle is 72 square units, name the possible location
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Answer:

<h3>#5</h3>

<u>Given vertices:</u>

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These have same x-coordinate, so when connected form a vertical segment.

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<u>Possible location of the remaining vertices (to the left from the given):</u>

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and

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<h3>#6</h3>

<u>Similarly to previous exercise:</u>

  • (5, -8) and (5, 4) given with the area of 48 square units

<u>The distance between the given vertices:</u>

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<u>The other side length is:</u>

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and

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4 0
3 years ago
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