Answer:
AC congruent to EC
Step-by-step explanation:
This problem is asking specifically to prove triangles congruent using HL.
HL is a method of proving triangles congruent. HL stands for Hypotenuse-Leg. If you can show that the hypotenuse and leg of one right triangle are congruent to the hypotenuse and leg, respectively, of another triangle, then the triangles are congruent.
Looking at triangle ABC and EDC, we see that the legs AB and ED are congruent. We already have a pair of corresponding congruent legs. Now we need a pair of hypotenuses.
You need AC congruent to EC.
<h3>
Answer: -22/7</h3>
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Explanation:
The fraction 6/(-7) is the same as -6/7
We have the two fraction -6/7 and 3/11 being divided
The denominators are 7 and 11 respectively.
The LCM of those two numbers is 77 since 7*11 = 77
If we multiply each of those fractions (-6/7 and 3/11) by 77, then we'll clear out those inner denominators to simplify this complex fraction into a nicer one.
77*(-6/7) = -66
77*(3/11) = 21
This means the original complex fraction becomes -66/21
We can further simplify this by dividing each part by the GCF 3
-66/3 = -22
21/3 = 7
Therefore, the final answer is -22/7
The standard form of 6x1x5x1/10 =3 x 10 ^0, any number raised to the power of 0 is 1 so 1 x 3 = 3
So hmm notice the picture below
a)
the center of the circle is the midpoint of those two folks
b)
the diameter is the distance between P and Q, or the length of that segment, and the radius is half the diameter
c)
so, from a), you found the h,k coordinates for the center, from b) you've got the radius
so, just plug them in here then
Answer:
15% probability that 7 adults selected at random from the town all have health insurance.
Step-by-step explanation:
(sample/population)^number of times selected
(76/100)^7 = (0.76)^7 = 0.15 = 15%
