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julsineya [31]
3 years ago
8

2

Mathematics
1 answer:
kozerog [31]3 years ago
3 0

Answer:

True

Step-by-step explanation:

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How do I solve for x?
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Solving:
\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
Make the Least Common Multiple (2,3,6)
2,3,6\:|2
1,3,3\:|3
1,1,1\:|\underline{2*3=6}


<span>Replace denominators and resolve:
</span>\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}
\frac{3(3+4x)}{6} + \frac{2(5-x)}{6} = \frac{29}{6}
Cancel the dominators
\frac{3(3+4x)}{\diagup\!\!\!\!6} + \frac{2(5-x)}{\diagup\!\!\!\!6} = \frac{29}{\diagup\!\!\!\!6}
3(3+4x) + 2(5-x) = 29
9 + 12x + 10 - 2x = 29
12x - 2x = 29 - 9 - 10
10x = 20 - 10
10x = 10
x =  \frac{10}{10}
\boxed{\boxed{x = 1}}\end{array}}\qquad\quad\checkmark


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