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saw5 [17]
4 years ago
11

To see her full heiht, a child that is 1 meter tall needs a mirror that is at least A) 033 m tall. 6) 050 m tall C) 075 m tall.

D) 1 m tall. E) depends on how far the child is from the mirror
Physics
1 answer:
svlad2 [7]4 years ago
7 0

Answer:

0.50 m tall

Explanation:

To see the full height of the child the height of the mirror should be half of the height of the child

As it id given that the height of the child is 1 meter so the height of the mirror is =\frac{height\ of\ child}{2}=\frac{1}{2}=0.5m

As it is a rule that to see the full any object the height of the mirror should be half of the height of the object

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A poster is 0.95m high and 1.0m wide how many digits follow the decimal point when the perimeter of the poster is expressed with
STALIN [3.7K]

Explanation:

It is given that,

Length of the poster, l = 0.95 m

Breadth of the poster, b = 1 m

The poster is in the shape of rectangle. For a rectangular shape, perimeter is equal to :

P = 2(l+b)

P=2(0.95+1)

P=3.9 m

(b) One digits, P = 4 m

(c) Two digits, P = 3.9 m

(d) Three digits, P = 3.90 m

6 0
3 years ago
A sample of an unknown material weighs 500.0 N in air and 400.0 N when submerged in an alcohol solution with a density of 0.70 ×
Papessa [141]

Answer:

500

Explanation:

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4 0
3 years ago
A student of weight 652 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude
miskamm [114]

Answer:

Explanation:

Given

Weight of person W=652\ N

At highest point Magnitude of the normal force F=585\ N

net force at highest point

F_{net}=W+F_c

where F_c= centripetal force

F_c=\dfrac{mv^2}{r}

F_{net}=F_{n}= Normal Force

585=652+F_c

F_c=-67\ N

Negative sign shows force is in upward direction

At bottom point centripetal force is towards the bottom

F_n=F_c+W

F_n=652+67

F_n=719\ N  

8 0
4 years ago
The force that opposes motion to moving parts is _____
Colt1911 [192]
The force that opposes motion to moving parts is F<span>riction</span><span>

Hope this helped!
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6 0
4 years ago
A solenoidal coil with 22 turns of wire is wound tightly around another coil with 330 turns. The inner solenoid is 21.0 cm long
Airida [17]

Answer:

0.00027646\ T

2.33\times 10^{-5}\ H

-0.04194 V

Explanation:

N_2 = Number of turns in outer solenoid = 330

N_1 = Number of turns in inner solenoid = 22

I_1 = Current in inner solenoid = 0.14 A

\dfrac{dI_2}{dt} = Rate of change of current = 1800 A/s

\mu_0 = Vacuum permeability = 4\pi \times 10^{-7}\ H/m

r = Radius = 0.0115 m

Magnetic field is given by

B=\mu_0\dfrac{N_2}{l}I\\\Rightarrow B=4\pi \times 10^{-7}\times \dfrac{330}{0.21}\times 0.14\\\Rightarrow B=0.00027646\ T

The  average magnetic flux through each turn of the inner solenoid is 0.00027646\ T

Magnetic flux is given by

\phi=BA\\\Rightarrow \phi=0.00027646\times \pi 0.0115^2\\\Rightarrow \phi=1.14862\times 10^{-7}\ wb

Mutual inductance is given by

M=\dfrac{N_1\phi}{I}\\\Rightarrow M=\dfrac{22\times 1.14862\times 10^{-7}}{0.14}\\\Rightarrow M=2.33\times 10^{-5}\ H

The mutual inductance of the two solenoids is 2.33\times 10^{-5}\ H

Induced emf is given by

\epsilon=-M\dfrac{dI_2}{dt}\\\Rightarrow \epsilon=-2.33\times 10^{-5}\times 1800\\\Rightarrow \epsilon=-0.04194\ V

The emf induced in the outer solenoid by the changing current inthe inner solenoid is -0.04194 V

3 0
3 years ago
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