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arlik [135]
4 years ago
15

A student of weight 652 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude

of the normal force on the student from the seat is 585 N. (a) What is the magnitude of at the lowest point
Physics
1 answer:
miskamm [114]4 years ago
8 0

Answer:

Explanation:

Given

Weight of person W=652\ N

At highest point Magnitude of the normal force F=585\ N

net force at highest point

F_{net}=W+F_c

where F_c= centripetal force

F_c=\dfrac{mv^2}{r}

F_{net}=F_{n}= Normal Force

585=652+F_c

F_c=-67\ N

Negative sign shows force is in upward direction

At bottom point centripetal force is towards the bottom

F_n=F_c+W

F_n=652+67

F_n=719\ N  

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The angular momentum of a flywheel having a rotational inertia of 0.142 kg·m2 about its central axis decreases from 7.20 to 0.14
luda_lava [24]

Answer:

3.3619 Nm

54.27472 rad

182.46618 J

86.88 W

Explanation:

L_i = Initial angular momentum = 7.2 kgm²/s

L_f = Final angular momentum = 0.14 kgm²/s

I = Moment of inertia = 0.142 kgm²

t = Time taken

Average torque is given by

\tau_{av}=\frac{L_f-L_i}{\Delta t}\\\Rightarrow \tau_{av}=\frac{0.14-7.2}{2.1}\\\Rightarrow \tau_{av}=-3.3619\ Nm

Magnitude of the average torque acting on the flywheel is 3.3619 Nm

Angular speed is given by

\omega_i=\frac{L_i}{I}

Angular acceleration is given by

\alpha=\frac{\tau}{I}

From the equation of rotational motion

\theta=\omega_it+\frac{1}{2}\alpha t^2\\\Rightarrow \theta=\frac{L_i}{I}\times t+\frac{1}{2}\times \frac{\tau}{I}\times t^2\\\Rightarrow \theta=\frac{7.2}{0.142}\times 2.1+\frac{1}{2}\times \frac{-3.3619}{0.142}\times 2.1^2\\\Rightarrow \theta=54.27472\ rad

The angle the flywheel turns is 54.27472 rad

Work done is given by

W=\tau\theta\\\Rightarrow W=-3.3619\times 54.27472\\\Rightarrow W=-182.46618\ J

Work done on the wheel is 182.46618 J

Power is given by

P=\frac{W}{t}\\\Rightarrow P=\frac{-182.46618}{2.1}\\\Rightarrow P=-86.88\ W

The magnitude of the average power done on the flywheel is 86.88 W

6 0
3 years ago
When an object has a net force of zero, then it is said to be in what?
Ganezh [65]

Answer: the object is said to be in a state of rest or uniform motion in a straight line

Explanation:Newton's first law of motion

3 0
4 years ago
A 3-kg object is attached to a spring and moving in simple harmonic motion. Its angular frequency is 20 rads/sec. When the mass-
Trava [24]

Answer:19.5 J

Explanation:

Given

mass of block=3 kg

angular frequency=20 rad/sec

spring constant k=\omega _n^2m=1200 N/m

we know total energy remain conserved

E_T at x=0.1 m

E_T=E_P+E_K

Where E_K=kinetic energy

E_P=potential Energy

E_P=\frac{1}{2}kx^2

E_P=600\times 0.01=6 J

E_K=\frac{1}{2}mv^2

E_K=\frac{1}{2}\times 3\times 3^2=13.5 J

E_T=13.5+6=19.5 J

When mass reaches amplitude its velocity becomes zero

there is only potential energy which is equal to Total energy

E_T=E_P=19.5 J

7 0
3 years ago
As you stand near a railroad track, a train passes by at a speed of 31.7 m/s while sounding its horn at a frequency of 218 Hz. W
Darya [45]

Explanation:

Given that,

Frequency of train horn, f = 218 Hz

Speed of train, v_t = 31.7 m/s

The speed of sound, V = 344 m/s (say)

The speed of the observed person, V_o=0\ m/s

(a) When the train approaches you, the Doppler's effect gives the frequency as follows :

f'=f(\dfrac{V}{V-v_t})\\\\f'=218\times (\dfrac{344}{344-31.7})\\\\f'=240.12\ Hz

(b) When the train moves away from you, the Doppler's effect gives the frequency as follows :

f'=f(\dfrac{V}{V+v_t})\\\\f'=218\times (\dfrac{344}{344+31.7})\\\\f'=199.6\ Hz

Hence, this is the required solution.

6 0
4 years ago
A ballon holds 24L at 45 k . find the volume if the temperature is increased to 911 k
Soloha48 [4]
911 k divided by 45 k equals the amount that you need to times 24L by.
The answer is ≈ 485.86L
6 0
2 years ago
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