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KiRa [710]
3 years ago
6

A poster is 0.95m high and 1.0m wide how many digits follow the decimal point when the perimeter of the poster is expressed with

the correct number of significant figures
A) zero digits
B) one digit
C)two digits
D)three digits
Physics
1 answer:
STALIN [3.7K]3 years ago
6 0

Explanation:

It is given that,

Length of the poster, l = 0.95 m

Breadth of the poster, b = 1 m

The poster is in the shape of rectangle. For a rectangular shape, perimeter is equal to :

P = 2(l+b)

P=2(0.95+1)

P=3.9 m

(b) One digits, P = 4 m

(c) Two digits, P = 3.9 m

(d) Three digits, P = 3.90 m

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¿cual es la velocidad de un haz de electrones que marchan sin desviarse cuando pasan a traves de un campo magnetico perpendicula
Elina [12.6K]

Answer:

La velocidad del haz de electrones es 1.78x10⁵ m/s. Este valor se obtuvo asumiendo que el campo magnético dado (3500007) estaba en tesla y que la fuerza venía dada en nN.

Explanation:

Podemos encontrar la velocidad del haz de electrones usando la Ley de Lorentz:

F = |q|vBsin(\theta)     (1)

En donde:

F: es la fuerza magnética = 100 nN

q: es el módulo de la carga del electron = 1.6x10⁻¹⁹ C

v: es la velocidad del haz de electrones =?

B: es el campo magnético = 3500007 T

θ: es el ángulo entre el vector velocidad y el campo magnético = 90°

Introduciendo los valores en la ecuación (1) y resolviendo para "v" tenemos:

v = \frac{F}{qBsin(\theta)} = \frac{100 \cdot 10^{-9} N}{1.6 \cdot 10^{-19} C*3500007 T*sin(90)} = 1.78 \cdot 10^{5} m/s            

Este valor se calculó asumiendo que el campo magnético está dado en tesla (no tiene unidades en el enunciado). De igual manera se asumió que la fuerza indicada viene dada en nN.

Entonces, la velocidad del haz de electrones es 1.78x10⁵ m/s.  

Espero que te sea de utilidad!                                        

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A rock is thrown upward from the level ground in such a way that the maximum height of its flight is equal to its horizontal ran
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\dfrac{v_t^2sin 2\theta}{g} = \dfrac{v_t^2sin^2\theta}{2g}

2sin\thetacos\theta = \dfrac{sin^2\theta}{2}

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