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katrin2010 [14]
3 years ago
8

Find the angles of a, b, c and d in the diagram

Mathematics
2 answers:
irina [24]3 years ago
6 0
I don’t know which diagram send a pic
lawyer [7]3 years ago
3 0
What is the diagram?
You might be interested in
The fair spinner shown in the diagram above is spun.
Katena32 [7]

Unable to provide a definitive answer due to lack of diagram.

Answer: 1/4

Step-by-step explanation:

Multiples of 6:

Multiples of 6 are numbers obtained when 6 is multiplied by an integer. Such as

(6*1) = 6, (6*2)=12, (6*3) = 18..... and so on.

Probability is calculated by finding the ratio of the required outcome and total possible outcomes.

Probability = required outcome / Total possible outcomes

P(multiple of 6) = number of multiples of 6 / total number of possible outcomes

If number of 6 multiples = 5 and

Total number of faces in the spinner = 20

Then :

P(multiple of 6) = 5/20 = 1/4

5 0
3 years ago
2. It takes 39,090 gallons of water to manufacture a new car. Sammy thinks that rounds up to about 40,000
Ainat [17]

Answer:

Susie rounded to the nearest thousandth.

Step-by-step explanation:

since the 100th place is 0 it would round down to 39,000 when you are rounding to the nearest thousand.

8 0
3 years ago
Find the balance in the account after the given period.
Likurg_2 [28]

Answer:

2240

Step-by-step explanation:

I think you find 3% of 2000 which is 60

Then you multiply that by 4 which is 240

Add it to the 2000

and get 2240

6 0
3 years ago
The plane x+y+2z=8 intersects the paraboloid z=x2+y2 in an ellipse. Find the points on this ellipse that are nearest to and fart
DiKsa [7]

Answer:

The minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

Step-by-step explanation:

Here, the two constraints are

g (x, y, z) = x + y + 2z − 8  

and  

h (x, y, z) = x ² + y² − z.

Any critical  point that we find during the Lagrange multiplier process will satisfy both of these constraints, so we  actually don’t need to find an explicit equation for the ellipse that is their intersection.

Suppose that (x, y, z) is any point that satisfies both of the constraints (and hence is on the ellipse.)

Then the distance from (x, y, z) to the origin is given by

√((x − 0)² + (y − 0)² + (z − 0)² ).

This expression (and its partial derivatives) would be cumbersome to work with, so we will find the the extrema  of the square of the distance. Thus, our objective function is

f(x, y, z) = x ² + y ² + z ²

and

∇f = (2x, 2y, 2z )

λ∇g = (λ, λ, 2λ)

µ∇h = (2µx, 2µy, −µ)

Thus the system we need to solve for (x, y, z) is

                           2x = λ + 2µx                         (1)

                           2y = λ + 2µy                       (2)

                           2z = 2λ − µ                          (3)

                           x + y + 2z = 8                      (4)

                           x ² + y ² − z = 0                     (5)

Subtracting (2) from (1) and factoring gives

                     2 (x − y) = 2µ (x − y)

so µ = 1  whenever x ≠ y. Substituting µ = 1 into (1) gives us λ = 0 and substituting µ = 1 and λ = 0  into (3) gives us  2z = −1  and thus z = − 1 /2 . Subtituting z = − 1 /2  into (4) and (5) gives us

                            x + y − 9 = 0

                         x ² + y ² +  1 /2  = 0

however, x ² + y ² +  1 /2  = 0  has no solution. Thus we must have x = y.

Since we now know x = y, (4) and (5) become

2x + 2z = 8

2x  ² − z = 0

so

z = 4 − x

z = 2x²

Combining these together gives us  2x²  = 4 − x , so

2x²  + x − 4 = 0 which has solutions

x =  (-1+√33)/4

and

x = -(1+√33)/4.

Further substitution yeilds the critical points  

((-1+√33)/4; (-1+√33)/4; (17-√33)/4)   and

(-(1+√33)/4; - (1+√33)/4; (17+√33)/4).

Substituting these into our  objective function gives us

f((-1+√33)/4; (-1+√33)/4; (17-√33)/4) = (195-19√33)/8

f(-(1+√33)/4; - (1+√33)/4; (17+√33)/4) = (195+19√33)/8

Thus minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

4 0
3 years ago
If 4^x+1 = 64, then what is the value of x^4
Olin [163]
4^{x} + 1 = 64 \\4^{x} = 63 \\ln(4^{x}) = ln(63) \\xln(4) = ln(63) \\x = \frac{ln(63)}{ln(4)}

(\frac{ln(63)}{ln(4)})^{4} = 79.78006702

The value of x⁴ is equal to 79.8006702
7 0
3 years ago
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