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Neporo4naja [7]

3 years ago

9

Hazel buys a sweatshirt. The cost of the sweatshirt is $40, however, the sweatshirt is 30% off. How much will Hazel pay for the

sweatshirt?

2 answers:

kiruha [24]3 years ago

8 0

Answer: $28

Explanation: if the sweatshirt is $40, then the percentage of 30% will be 12. 40 - 12 = 28

Vedmedyk [2.9K]3 years ago

5 0

Answer:

12 I think????

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Step-by-step explanation:

In order to find this, start by looking for the cost per student. We can do this by dividing the overall cost by the number of students.

$12/4 students = $3 per student.

Now we take that unit rate and multiply by the new number of students.

$3 * 10 students = $30 total spent.

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2 years ago

Round 0.00076511 to one significant figure

FrozenT [24]

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Step-by-step explanation: Hope this helps :)

6 0

3 years ago

Help me, Don't spam

Anuta_ua [19.1K]

QuestioN:

A container in the shape of of a frustum of a cone having diameters of its two circular faces as 35 cm and 30 cm and vertical height 14 cm, is completely filled with oil. if each of oil has mass 1.2 g, then find the cost of oil in the container if it costs $ 40 per kg.

${\large{\frak{\pmb{\underline{ Clearly,\:we\: have}}}}}$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\bullet\:r = \bf\dfrac{30}{2}\:cm=15\:cm$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\bullet\:R = \bf\dfrac{35}{2}\:cm=17.5\:cm$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\bullet\:h = 14\:cm$

$\:\:\:\:\:\:\:\:\:\:━━━━━━━━━━━━━━━━━━━━$

$\:$

${\bold { \underline{\small{Now,}}}}$

$\:\:\large{\ddagger}\underline {\footnotesize{\boxed{\frak{Volume_{(container)}={\frak{\orange{\bigg\{\bf\dfrac{1}{3}\pi (R^2+r^2+Rr)h\bigg\}cu}}}}}}}$

$\:\:$

$\:$

$\sf {\scriptsize\Bigg[\bf\dfrac{1}{3}\times \bf\dfrac{22}{7}\times\Bigg\{\bigg(\dfrac{35}{2}\bigg)^2+(15)^2+\dfrac{35}{2}\times 15\Bigg\}\times 14 \Bigg]cm^3}$

$\:\:$

$\:$

$\sf \:\:\:\:\:\rightarrowtail\: \dfrac{44}{3}\times\bigg(\dfrac{1225}{4}+225+\dfrac{525}{2}\bigg)cm^3$

$\:\:$

$\:$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\rightarrowtail\: \bigg( \dfrac{44}{3}\times \dfrac{3175}{4}\bigg)cm^3$

$\:\:$

$\:$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\rightarrowtail\: \bigg( \dfrac{3175 \times 11}{3}\bigg)cm^3$

$\:\:$

$\:$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\small{\underline{\mathcal{\red{Mass\:of\:1\:cm^3\:of\:oil\:=\:1.2\:g }}}}$

$\:\:$

$\:$

$\:\:\:\:\:\:\:\sf \footnotesize{Mass_{(oil\:in\:the\: container)}=\bigg( \dfrac{3175 \times 11}{3}\times1.2 \bigg)\:g}$

$\:\:$

$\:$

$\sf\:\:\:\:\:\:\:\:\rightarrowtail\:\bigg( \dfrac{3175 \times 11}{3}\times\dfrac{12}{10}\times\dfrac{1}{1000}\bigg)\:kg$

$\:\:$

$\:$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\rightarrowtail\:\dfrac{1397}{100}\:kg\:=13.97\:kg$

$\:\:$

$\:$

$\bf\twoheadrightarrow$ Cost of oil at $40 per kg = $(13.97×40) $\:\:=\:\large{\underline{\mathcal{\purple{\$\:558.80.}}}}$

8 0

3 years ago