51 blue fish.
If there is 34 to 50 blue to red fish in tank A. Then tank B is 51 to 75. Because 75 is 1.5 times larger than 50 you have to multiply 34 by 1.5 to get 51.
Step-by-step explanation:
Given (2x + 23), (8x + 2) and (20x - 52) are three consecutive terms of an arithmetic sequence.
(8x + 2) - (2x + 23) = (20x - 52) - (8x + 2)
or, 6x - 21 = 12x - 54
or, 12x - 6x = - 21 + 54 = 33
or, 6x = 33
or, 2x = 11
∴ x = 11/2
∴2x + 23 = 2 × 11/2 + 23 = 34
8x + 2 = 8 × 11/2 + 2 = 46 and
20x - 52 = 20 × 11/2 - 52 = 110 - 52 = 58
34, 46 and 58 are three consecutive terms of an arithmetic sequence.
∴ Common difference(d) = 46 - 34 = 58 - 46 = 12, it is proved.
Hence, the common difference of the sequence is 12.
Answer:
Answer B is the correct answer..
cot(theta)=cos(theta)/sin(theta)
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