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3 years ago

WHAT IS 18 TONS 42 POUNDS DEVIDED BY 3

Mathematics

2 answers:

Alecsey [184]3 years ago

4 0

A ton is 2,000 pounds so multiply 2,000 x 18

2,000 x 18 = 36,000 pounds, now add the 42 pounds to the 36,000

36,000 + 42 = 36,042 pounds. Now divide 36,042 by 3

36,042 ÷ 3 = 12,014

Your answer is 12,014 pounds

If you need your answer in tons it's 6.007 tons

Calculations for pounds to tons

12,014 ÷ 2,000 = 6.007

Hope this helps. :)

neonofarm [45]3 years ago

3 0

Just divide each value individually.

$\frac{18t}3 = 6t \\\\ \frac{42\ lbs}3 = 14\ lbs$

Thus a third of 18t. and 42 lbs. is 6t. and 14 lbs.

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3 years ago

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3 years ago

In a rectangle ABCD if AB=4x and DC=7x-9,find the length of AB.(Lengths are in cm).

myrzilka [38]

Answer:

12 cm

Step-by-step explanation:

AB and DC are parallel to each other, so they are the same length. Set their lengths equal to each other and solve for x

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8 0

2 years ago

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago